Recent content by blost

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    Calculating Normal Mode: 2 Bars & Metal Spring

    so... 2 different theta it's a bit too complicated for me... how i must modificated my solution ?
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    Calculating Normal Mode: 2 Bars & Metal Spring

    (distance between bars-d) sory but english is not my first language and... when I put "pin" in my dict there is only "penis" :D Theta is a delfection angle of bar...
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    Calculating Normal Mode: 2 Bars & Metal Spring

    ok... I tried do It better: M_1=- \frac{1}{2}d mgsin \theta M_2=-kxcos\theta d \Leftrightarrow M_2=-ksin\theta d cos \theta d M_w=- \frac{1}{2}d mgsin \theta-ksin\theta d^2 cos \theta sin\theta \approx \theta cos\theta \approx 1 M_w=- \frac{1}{2}d mg \theta-kd^2\theta I...
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    Calculating Normal Mode: 2 Bars & Metal Spring

    \varepsilon = \frac{M}{I} I=1/3 ml^2 M=F*l F=-kx \Rightarrow F=-ksin\alpha l \varepsilon = \frac{-ksin\alpha l^2}{1/3 ml^2} \varepsilon =-3 \frac{ksin\alpha}{m} I try my best but I think it is wrong...
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    Calculating Normal Mode: 2 Bars & Metal Spring

    1) yes, there is some sinusoidal force but I think we can forget it. I needed it to second part of task... I have no idea how to do it... I Must write some differential eguation, yes ? I still have big problems with differential equations...
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    Calculating Normal Mode: 2 Bars & Metal Spring

    so... there are 3 diferent forces 1) force which causes tense of springs F=F_0cos(\omega t) 2) force of gravity (I susspect we can pass over it because for small deflection of bars is really little... 3) Restoring force of spring F=-kx What shall I do next ?
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    Calculating Normal Mode: 2 Bars & Metal Spring

    2 metal, thin, bars (length=l, mass=m) are hunging on same height (distance between bars-d) Lower end of bars are conected by metal spring (mass=0, k-spring constant, d-length) My problem is how to calculate a normal mode.
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    Alternating current+Oscillation

    Ok. I know why the bars are oscillating, but my main problem is how. The frequency of force is 2xf, isn't it ? and now... there is problem with resonance... I must calculate a resonance frequency of coils or bars ? The mas of cails =0 so i suppose that a normal mode of an oscillating -->0.
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    Calculating Escape Velocity on the Equator: Is It Possible?

    thanks. Now i know... by the way... sorry for my not-recherche language. English is not my native language (I'm 17 from Poland-3 h eng for a week ;/ 37 people in my class ;/ as like Cambodia... ), so please be tolerate :)
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    Calculating Escape Velocity on the Equator: Is It Possible?

    I know that KE+Pe>0. And I know that escaping mass isn't locked in a circular orbit around the earth, but it's still got a kinetic energy from Earth rotation, so i don't know, is Kinetic energy a sum of kinetic energy of Earth rotation and energy which must be inserted to this object?
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    Calculating Escape Velocity on the Equator: Is It Possible?

    hello... I've got some small problem with Escape velocity. So... is it dependent on geographic coordinate ? I suppose "Yes!"... but is it true? Using conservation of energy, I calculate this velocity on equator this way: \frac{mv^2}{2}= \frac{GMm}{R} - \frac{m(2 \pi R)^2}{T^2*R } Am I right ?
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    Alternating current+Oscillation

    Bob, I will be grateful if You could say something more... My main problem is How the force is conected with frequency.
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    Alternating current+Oscillation

    so You mean that there will be a force betwen each of roll ? First i thing that the main force will be come from the bars... You know...F~I^2/d * l... Could You say something more ? But still I don't know how to conect a force and frequency... maybe f will be conected with period of...
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    Alternating current+Oscillation

    Hi, It's my first poste here. 2 metal, thin, bars (length=l, mass=m) are hung on same height (distance between bars-d) Lower end of bars are conected by metal spring (mass=0, k-spring constant, d-length) Upper end of bars are connected with alternating current source (f-frequency). For...
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