Hello and thanks for the response, seems I can't edit the post.
The question is in the title, I don't know any equations other than the one given, you'll have to forgive it being in the wrong place.
My proposal does not include a question, it's a proposal that is phrased as one.
Cheers.
Homework Statement
I don't know much about physics, I'm using-
F=m*a
Homework Equations
So say we got our 2 containers with a straight passage between them (they're cylinders for the sake of the question), and the right one has double the radius.
So I'm assuming there are 2 forces...
Thanks for the great answers, just a few more questions:
Shouldn't gravity cause the pressure on top to be greater? I mean particles being pulled into the object.
Secondly, I believe I'm misunderstanding something and would love clarification:
Say I hit a billiard ball with a stick, it starts...
Homework Statement
This isn't homework, just pursuing some physics on my own and curious.
Homework Equations
So I've got 2 questions which have been sort of bothering me.
1-When I throw something into the air, does it stop for a tiny time at each molecule it meets (Newtons third law)...
Why is it not possible to deriviate 2cx and relate to c as if it is a constant? So you have y=2cx^2
y'=(2cx), g'=-1/(2xc), so g= ln((2xc)/-2c'+C, wouldn't this be the answer?
Thanks, you are all great :)
Bonaparte
So were trying to prove the second one smaller then first (I think), that is:
|sqrt(a)-e|<|a/e-e|
sqrt(a)-e<a/e-e (since both are positive, as using the given inequality subtract e from both sides) so sqrt(a)<a/e
e*sqrt(a)<a,
but e is not necessarily smaller then sqrt a, what am I missing?
There :)
Homework Statement
Let e be the number close to sqrt(a) by Newtons Method (That is picking a number, diving a by it, and taking their average, divide a by average, get a number, find their average, so on). Using |e<sqrt(a)+e|
prove that if |a/e-e|<1/10
then |sqrt(a)-e|<1/10
Note that e is...
Its a lot of messing around with, but I'll give you the basic idea, note that when you expand, the integers turn out to be sum of squares, that is (n-1)(n)(2n-1)/6. The rn turn out to be (n-1)rn. You just do this to the different terms to get the final thing, which then you might be able to...
Homework Statement
So I have happily exploring function when I got to the equation 0 = 1/2(e^(2x))-(e+1)(e^x) +ex.
Homework Equations
Well, I guess the quadratic formula can help, although I can't seem to get to a situation where I can use it.
The Attempt at a Solution
I played...
Could you explain how you got from 2cx/x^2 = 2/x? and then when you had y'/y=2/x, and multiplied both sides by y, how did you get 2/xy? should it not be 2y/x?
I actually thought you would have 2cx*g'x = -1, g'x=-1/2cx
gx = (-1/(2c))*ln(x)+C?
Thanks, Bonaparte
Homework Statement
While I was in school I thought to see what a function whose derivative is always perpendicular to another functions derivative would look like, so for example for X^2 we have -ln(x)/2.
Homework Equations
Well all those integration tables I guess
The Attempt at a...
I'll give you an even bigger hint than Symbol and ehild gave:
a(n) = a1 + (n-1)d
substitute 11...
53 = a1+10d
you can do the rest ;)
Thanks and good luck, Bonaparte