Recent content by Boomzxc

https://www.dropbox.com/s/t5lv4nlunn35ok8/phy1.PNG?dl=0 https://www.dropbox.com/s/ktc9pj7qmqhejrv/phy2.PNG?dl=0 https://www.dropbox.com/s/qbjz1p1gokvsgj2/Capture3.PNG?dl=0 I googled "polarizer film diagram" and "malu's law" and "polarizer physics" to obtain the pictures in this thread. I...

I think by EPE = 1/4πε( Qproton Qe-) /r, As r increase, EPE becomes less -ve(i.e. more +ve) , indicating higher energy level

Ahh yes ! Okay, i understand better now. Yes, no energy is needed for an electron to maintain an orbit as acceleration is perpendicular to direction of motion Removing e- from a atom or transitioning it to a higher energy level requires energy. I realized my misconception. What about the...

Ahh yes ! Okay, i understand better now. Yes, no energy is needed for an electron to maintain an orbit as acceleration is perpendicular to direction of motion Removing e- from a atom or transitioning it to a higher energy level requires energy. Thank you , orodruin !

However there's one aspect i don't understand. In chemistry, the electron shell of higher principal quantum number, has higher energy levels !

I see. Yes, if a electron is closer to a proton, potential energy is more negative, hence less.

[SORRY TYPO] : It's position exists as a probability density OR* radial probability function is it possible to edit the contents of the post?

Is it possible to edit the contents of the thread?

[SORRY TYPO] : It's position exists as a probability density OR* radial probability function

Alright, maybe not directly related. E=WD/t =(F×D)/t Would u elucidate abt my first point regarding energy, And the 2nd point regarding that e- further away having weaker attraction compared to a e- nearer to nucleus, Both points in which are contrary to the fact that electron shells of...

Using electrical potential energy =1/4πεo Q1Q2/r , a particle further away from nucleus has lower magnitude of energy Using coulomb's law, a particle further away from nucleus experiences weaker attraction, hence less energy is needed to maintain orbit* around that e-shell compared to a...

[SORRY] Thread's name is truncated! Should've been " Why does an electron shell further away from nucleus has higher energy level "

Using electrical potential energy =1/4πεo Q1Q2/r , a particle further away from nucleus has lower magnitude of energy Using coulomb's law, a particle further away from nucleus experiences weaker attraction, hence less energy is needed to maintain orbit* around that e-shell compared to a...

ΣF=ma In the direction of centripetal acceleration, T-Wcosθ=mv^2/r?

Weightcosθ?