Recent content by Boozehound

alright i got it thank you very much!

what formula would i use for that? i looked in my book and i couldn't come up with a formula...

A 2.65g aluminum bullet at 31.4°C is fired at a speed of 209 m/s into a large block of ice at 0°C, in which it embeds itself. What quantity of ice melts? Q=(9.00E2)(.00265)(31.4)=74.889J 74.889J=m(33.5E4)=2.23E-4kg so i get a final answer of 2.23E-4kg but its wrong. i think I am either...

yes that was it...i used 3350 instead of 3550 on accident. thank you.

The latent heat of vaporization of H2O at body temperature (37.0°C) is 2.38E+6 J/kg. To cool the body of a 71.9 kg jogger [average specific heat capacity = 3550 J/(kg*°C)] by 1.10°C, how many kilograms of water in the form of sweat have to be evaporated? Q=cmt Q=mL...

How much heat is required to change a 46.6 g ice cube from ice at -12.5°C to water at 53°C? (if necessary, use cice=2090 J/kg°C and csteam= 2010 J/kg°C) then i used Q=cmt and Q=mL Q=(2090)(.0466)(12.5)=1217.425J Q=(.0466)(33.5E4)=15611J Q=(2010)(.0466)(53)=4964.298J then when i add...

i got it..i just didnt take the square root of the velocity. simple overlook.

but then again it could be the right formula but i have the wrong numbers

cause i put in the answer and its the wrong answer..

ok i did the kinematics and i found the velocity to be 168.952m/s. and i found a formula E=vBL and if i plug in thoes values that i found before E=168.952(1.67E-5)11.8 and E equals .0332. but again i think that's the wrong formula obviously.

thats what i thought i did. to find time i took the height that was given of 8.62m and i took 9.80m/s^2 and divided it by 8.62m and got 1.137s^2 and i took the square root of that to find just seconds and i got 1.06s. then i took 8.62m and divided it by 1.066s to get a velocity of 8.132m/s. but...

A 11.8m long steel beam is accidentally dropped by a construction crane from a height of 8.62m. The horizontal component of the Earth's magnetic field over the region is 16.7μT. What is the induced emf in the beam just before impact with the Earth, assuming its long dimension remains in a...

ah! yeah now that you say it that doesn't make sense.. thank you very much!

44.400=37.800[1+X(56.000-27.800) 44.400=37.800[1+X(28.2) 44.400=37.800[1+28.2X] 44.400=37.800[29.2X] 1.1746=29.2X .0402=X those are the steps i used...im not too sure about what to do with the 1+X part but that might be where I am going wrong.

A coil of wire has a resistance of 37.800 Ω at 27.800 °C and 44.400 Ω at 56.000 °C. What is the temperature coefficient of resistivity? Do not enter units. Equation: R=R0[1+α(T-T0)] then i plugged in number to make the equation look like this: 44.400=37.800[1+X(56.000-27.800)] and i...