Temperature Coefficient of Resistivity

AI Thread Summary
To find the temperature coefficient of resistivity, the equation R=R0[1+α(T-T0)] is used with resistance values at two different temperatures. The initial calculations incorrectly combined terms with different units, leading to an incorrect value for X. The correct approach involves isolating X by rearranging the equation to (44.4/37.8) - 1 = 28.2X. This adjustment clarifies the mistake and allows for the proper calculation of the temperature coefficient. Understanding unit consistency is crucial in solving such equations accurately.
Boozehound
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A coil of wire has a resistance of 37.800 Ω at 27.800 °C and 44.400 Ω at 56.000 °C. What is the temperature coefficient of resistivity? Do not enter units.

Equation: R=R0[1+α(T-T0)]

then i plugged in number to make the equation look like this:

44.400=37.800[1+X(56.000-27.800)]

and i solve for X and i get X=.0402 and its wrong...

anyone see something i dont?
 
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Can you show more of your steps to your final answer? You're making a mistake somewhere.
 
44.400=37.800[1+X(56.000-27.800)

44.400=37.800[1+X(28.2)

44.400=37.800[1+28.2X]

44.400=37.800[29.2X]

1.1746=29.2X

.0402=X

those are the steps i used...im not too sure about what to do with the 1+X part but that might be where I am going wrong.
 
Last edited:
Boozehound said:
44.400=37.800[1+X(56.000-27.800)

44.400=37.800[1+X(28.2)

44.400=37.800[1+28.2X]

44.400=37.800[29.2X]

1.1746=29.2X

.0402=X

those are the steps i used...im not too sure about what to do with the 1+X part but that might be where I am going wrong.

You can't add the 1 to the 28.2, since the units are not the same (it doesn't make sense to do that). You must go

(44.4/37.8) - 1 = 28.2X

in the next step to isolate X.
 
ah! yeah now that you say it that doesn't make sense.. thank you very much!
 
You're welcome. :smile:
 
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