Recent content by bruno67

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    Laplace Inversion: Why Contour Must Exceed Singularities

    Is it so that f(t) vanishes for t<0?
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    Laplace Inversion: Why Contour Must Exceed Singularities

    Maybe I am just being stupid, but I don't understand why in the Laplace inversion formula (\mathcal{L}^{-1} F)(t) = \frac{1}{2\pi i} \int_{\sigma-i\infty}^{\sigma+i\infty} e^{st} F(s) ds the contour of integration must be chosen so that \sigma is greater than the real part of all...
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    Estimating Error in Acceleration: Can We Do It?

    Denote by V(x) the speed of a particle at position x. Let's call v(x;\zeta) a measurement of it, which depends on some parameter \zeta, and denote the error by \epsilon(x;\zeta)=v(x;\zeta)-V(x). In order for the measurement to produce meaningful results, we must have some kind of error...
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    Approximating Error in $\partial_x u(x;\eta)$

    I have a quantity U(x), x>0, which I cannot calculate exactly. Numerically, I can calculate an approximation u(x;\eta), for \eta>0, which is very close to U(x) if \eta is small enough. I know that the error \xi(x;\eta)=u(x;\eta)-U(x) satisfies an estimate |\xi(x;\eta)|\le E(x;\eta) where...
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    Integrability & Differentiability of a Function: Implications for Derivatives

    Even in that case, I can't find an error with my proof.
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    Integrability & Differentiability of a Function: Implications for Derivatives

    A function f is both integrable and infinitely differentiable, i.e. f\in L_1(\mathbb{R}) \cap C^{\infty}(\mathbb{R}). Is it correct to say that this implies that the derivatives of f are also in L_1(\mathbb{R})? My reasoning: we have I<\infty, where I=\int_{-\infty}^{\infty} f(x) dx = [x...
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    Bound for S: Sum of n^k e^(-an)

    I got it. S(k) is bound by the integral S\le \int_1^{N+1} x^k e^{-ax} dx
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    Bound for S: Sum of n^k e^(-an)

    I am looking for a bound for the following expression S=\sum_{n=1}^N n^k e^{-an} where a>0 and k=1, 2, 3, or 4, apart from the obvious one: S\le \frac{n+1}{2} \sum_{n=1}^N e^{-an} = \frac{n+1}{2} \frac{1-e^{-Na}}{e^a-1}
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    Remainder estimate for product series

    Suppose I have two series A=\sum_{n=0}^\infty a_n B=\sum_{n=0}^\infty b_n and I have estimates for the remainders of each one: \sum_{n=N}^\infty a_n \le R^N_A \sum_{n=N}^\infty b_n \le R^N_B Consider the product series AB=\sum_{n=0}^\infty c_n where c_n=\sum_{i=0}^n a_i...
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    Is there a shorthand for an indicator function of a positive integer?

    Is there a convenient shorthand for an "indicator function" of a positive integer n which vanishes if n is odd and is equal to 1 otherwise? I was thinking about something like \mathbb{1}_{\{\mathrm{mod}(n,2)=0\}}(n), but I'm not sure if this would be considered acceptable mathematical notation.
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    Calculating Incomplete Gamma Function for Complex Arguments

    How do I calculate the integral \int_{ix}^{i\infty} e^{-t} t^{-s-1}dt, where x>0, s>0? Mathematica gives \Gamma(-s,ix), where \Gamma(\cdot,\cdot) is the incomplete gamma function, but I am not sure how to justify this formally.
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    What combinations satisfy this complex exponentiation property?

    Thanks, so it holds in all cases except the (-,-) one. In that case we have [(-ia) (-ib)]^\alpha = (-ia)^\alpha (-ib)^\alpha (-1)^{2\alpha}.
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    What combinations satisfy this complex exponentiation property?

    Suppose we have the product [(\pm ia) (\pm ib)]^{-\alpha} wherea, b, \alpha >0. For which of the combinations (+,+), (+,-), (-,+), and (-,-) is the following property satisfied? [(\pm ia) (\pm ib)]^{-\alpha}=(\pm ia)^{-\alpha} (\pm ib)^{-\alpha}
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    Is there a way to calculate this difficult integral analytically?

    Still, I would be curious to know how you did it, even for b=0.
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