Recent content by BUI TUAN KHAI

  1. BUI TUAN KHAI

    Measured result is equal to expectation value

    Thank you for you explanation.
  2. BUI TUAN KHAI

    Measured result is equal to expectation value

    As I think, What we observe from the measurement is the eigenvalue. According to the question, it means that the eigenvalue = expectation value ? If we have an observable A, and a physical state |a>, we have A|a> = a|a>. <A> = <a|A|a> = a<a|a> = a Thus, this case only happens if: |a> is the...
  3. BUI TUAN KHAI

    Measured result is equal to expectation value

    Can I ask a basic question. This was a question in a test, I could not solve this. When is it true that the result of a single measurement for a dynamical variable is equal to the expectation value of the operator corresponding to that dynamical variable? Thank you for your help. Sincerely...
  4. BUI TUAN KHAI

    Bmax in Bohr's calculation for energy loss of charged particles (classical case)

    Can you explain it for me? This will be helpful for me. because i have a report tomorrow.
  5. BUI TUAN KHAI

    About the mass stopping power of muon

    Dear all, I calculated the mass stopping power of muon but the result was 1.4 MeV.g^-1.cm^2. I calculated by BEthe-Bloch formula. I think it is wrong. since I looked up in the books and internet, this value is about 2 MeV.g^-1.cm^2. Can you help me. I also send the excel file as below.
  6. BUI TUAN KHAI

    Bmax in Bohr's calculation for energy loss of charged particles (classical case)

    [FONT=Times New Roman] Dear Fek, But can I know the reason why t = b/v ≤ τ = 1/ν ? I don't understand the physics meanings.
  7. BUI TUAN KHAI

    Bmax in Bohr's calculation for energy loss of charged particles (classical case)

    [FONT=Times New Roman] I think T = 2b/v is right. Since the electric energy is E = Ze^2/b=mv^2/2 and T = mv=2E/v, thus, T = 2Ze^2/bv.
  8. BUI TUAN KHAI

    Bmax in Bohr's calculation for energy loss of charged particles (classical case)

    [FONT=Times New Roman] Dear Fek, Based on the impulse approximation, T = 2b/v. but the time for interaction that I mentioned is t = b/v. they are not the same ! Please help. I am also thinking. Thanks.
  9. BUI TUAN KHAI

    Bmax in Bohr's calculation for energy loss of charged particles (classical case)

    [FONT=Times New Roman]Dear all, I have inquiries about the Bohr's calculation for energy loss of charged particles. These inquires are from the "Techniques for Nuclear and Particle Physics Experiments" (W.Leo). On page 23 of this book, it is written that: [FONT=Times New Roman]the the...
  10. BUI TUAN KHAI

    Leo's book [energy loss of heavy charged particles]

    @e.bar.goum : Thank you for your response "mediated by the electromagnetic interaction" ? what do you mean about this? Could you please explain more clearly for me?
  11. BUI TUAN KHAI

    Leo's book [energy loss of heavy charged particles]

    Dear all, I am reading the "Techniques for Nuclear and Particle Physics Experiments" of W.R.Leo. I am confused when reading the section 2.2. Energy Loss of Heavy Charged Particles in Atomic Collisions (page 21). At the beginning of the second paragraph (from the bottom up), it is written that...
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