Recent content by buttretler

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    MHB Absolute Value Graph: Explaining |2-x| Horizontal Translation Right

    I think the second way I understand better, it still leaves me hazey because if |x-2|=|2-x| would mean no shift is taking place. And the only way at my level to show it is to the right, is a table of values with f(0),f(1) and f(2). Either way thanks for the further inlightenment.
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    MHB Absolute Value Graph: Explaining |2-x| Horizontal Translation Right

    Can someone explain to me why |2-x| would have a horizontal translation to the right? When I've always been taught that anytime you see a [+] it will translate to the left. The graph would be a regular |x| graph but it is shift 2 spots to the right. Thanks to anyone for help
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    MHB Why Does 0.27 Degrees Equal 3π/2000 in Trigonometry?

    Thank you so much. Once you go days studying, you start to lose focus on simple things. Thanks again.
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    MHB Why Does 0.27 Degrees Equal 3π/2000 in Trigonometry?

    Couldn't figure out why. Where 0.27 deg =3pi/2000. Now the only way I could figure this out is 270 deg = 3pi/2. multiply by 1000 to get the 270 and the 2000, but gives 3000pi/2000? Anyone tell me where this came? Thanks
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    Impulse and Momentum, 2 dimension

    Been stuck on this question for days and any help would be greatly appreciated A baseball going horizontally at 32.0 m/s [E] with a mass of 0.152 kg is hit by a bat for 0.002 seconds. the velocity after the ball after contact is 52.0 m/s [W 20 N] Find the impulse experienced by the ball...
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    Help with Inclinded Plane Problem

    Really? I just can't seem to understand why the weight of the block is irrelavent. The fact that the staic friction is 0.4 would mean that the angle at which something slides on a plane with always be 22 degrees, like if it were 10 kg or 15kj, would the angle always be 22? I just can't wrap my...
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    Help with Inclinded Plane Problem

    Hello Everyone! Homework Statement I'm having trouble with this problem. I'm sapose to figure out at what angle a 5 kg block beings to slide with a static coefficient of 0.4. [b]3. The Attempt at a Solution [/b So far I've been working it out through trigonometry and I've gotten...
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