I think it is neither. It makes sense when you are calculating total % composition of Cadmium Sulphate that you would divide 208.47 by 1208.47 instead of just 1000. Because 1000g would just be the mass of the solvent not the soln.
What is the percent CdSO4 by mass in a 1.0 molal aqueous solution?
My attempt:
CdSO4 is 208.47g/mol
1.0 molal = 1 mol CdSO4/1kgH2O
Converted mols to grams, and kg to g.
208.47g Cd/1000g H2O = .20847
.20847 x 100 to get % mass = 20.8%
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