Recent content by calculator20

Thank you for your help. I used the quoted value from the textbook but I’ve just spotted that value for copper below it is identical so it could be a mistake in the book. Thanks again

I’m fine with part a, answer 3.3 x10^6 but I’m getting 0.00045 for part b when it should be 2.8x10^-4, what am I missing? e = (1500x18)/(1.3x10^11 x 0.000452389)

49cm, thank you!

The answer is 127.04g. I’m getting close but can’t get the answer. Using 9.81 for gravity, the force where the balance is is 2.10(58146)N As it is balanced 2.10N x 0.29m = W x 0.50m where 0.50 is the centre of mass That gives W = 1.22N = 124.5g?

No they hadn't appeared when I responded, not sure your abrupt response was entirely necessary!

Ok thanks for your help

Ok yes understood. That aside is acceleration zero for terminal velocity? I don't think it is?

I've just read somewhere that acceleration is zero when an object is at terminal velocity? I think it's wrong but wanted to check if I'm right? Yes the resultant force is zero but gravity doesn't disappear so presumably acceleration due to gravity is constant? Terminal velocity means constant...

Thank you so much that makes sense!

R2/2R?

(1/2R2 + R)/R?

1/2 R2/R +R/R Do I have to separate the square now? Sorry, still can't see how I'm going to get the 2/3. Really appreciate your help so far

Ok so ((RxR)/(R+R)) + R (2R/2R) + R? I don't think that's right but don't understand how I would get the same denominator either

I think it's (R1xR2)/(R1+R2) for the parallel part then (R1xR2)/(R1+R2) + R to add the series part in but don't know how to combine those?

Homework Statement An electric circuit consists of 3 identical resistors of resistance R connected to a cell of emf E and negligible internal resistance. What is the magnitude of the current in the cell? (in the diagram two of the resistors are in parallel with each other then the other in...