Recent content by Casimi

Thank you! You just saved my grade!

I came up with 2.51m/s but it is still showing as incorrect. Is this the solution that you arrived at?

Yes, I tried that and am still not arriving at the right answer. 5.06/6.10 will give .82. If I integrate from -5.06t+3.05t^2 [0 to .82] + 5.06t+3.05t^2 [.82 to 1.2] I am still going to get : 5.06t +3.05t^2 [0 to 1.2]? Please help me out.

(-5.06+6.10t) - that is my answer after differentiating. Integrating the absolute value, I have 5.06t+3.05t^2 with integral limits of 0 to 1.20. When I put the values in the integral, I get 9.456 and when divided by 1.2, I get 7.88 which is not the correct answer.

I tried that but I am still not arriving at the correct answer. I arrive at a number far larger than it should be. I cannot figure out what I am doing wrong.

Homework Statement The position of a particle as a function of time is given by x = (-5.06 m/s)t + (3.05 m/s2)t2. Calculate the average velocity of the particle from t = 0 to t = 1.20 s. -1.40 m/s (this is correct, from my calculations) 2nd part: Calculate the average speed from t = 0 to...

No need, I finally figured it out :)

Homework Statement A ball, dropped from rest, covers three-fifths of the distance to the ground in the last second of its fall. From what height was the ball dropped? The Attempt at a Solution I have spent the past thirty minutes attempting to figure this out. I initially used a kinematic...

It seems like I should take more time to organize my thoughts and perform my algebra correctly. Simple mistakes are always my downfall!

It seems as if I derived the wrong formula via a mistake in my algebra. Thank you so much!

Homework Statement An athlete executing a long jump leaves the ground at a 31.6° angle and travels 7.78 m. What was the take-off speed? I have tried to solve this question but somehow keep arriving at the wrong answer. The formula that I derived is : distance=V(initial)*sin^2(theta)/g...