Recent content by chaslltt

Homework Statement Two small objects, A and B, are fixed in place and separated by 2.46 cm in a vacuum. Object A has a charge of +1.18C, and object B has a charge of -0.937C. How many electrons must be removed from A and put onto B to make the electrostatic force that acts on each object an...

does this look right ln y= 18/x^4 ln x 1/y= 18/x^5 + -72x^-5 ln x = y 18/x^5 + -72x^-5 ln x then just plug in y ?

well the computer told me that solution is wrong also so any other advice would be helpful

alright so then i should get ln y = ln (x^(18/x^4)) 1/y = 18/x^4 ln x = y 18/x^4*1/x = y 18/x^5 = x^(18/x^4)*18/x^5 ?

Homework Statement y = x^(18x^-4) Homework Equations chain rule dy/dx a^x = a^x ln a The Attempt at a Solution first i used the second equation from above to get x^(18/x^4)*ln(x) then i use the chain rule to get x^(18/x^4)*ln(x)*(-72x^-5) the computer program i am using is...

alright i ended up getting g'(x)= 2x- sin g(x)/(1+cos g(x) so then i plug in the 0 but what is g(0)

cos(g(x))*g'(x)

d/dx f(g(x)) would be f'(x)g(x)*g'(x)

my first step took me to this: g'(x) + xcos g'(x) + sin g(x) = 2x then i set it equal to g'(x) g'(x)= 2x- sin g(x)/xcos(1) I would then plug in 0 but that makes the denominator 0

Homework Statement If g(x) + x sin g(x) = x^2 find g'(0) Homework Equations The Attempt at a Solution At this point I have tried a few things but hit deadends. Any help would be appreciated.

thank you

Homework Statement find limit of x as it approaches infinite sqrt(x^2+ax)-sqrt(x^2+bx) a and b are not given Homework Equations The Attempt at a Solution Looking at this equation I first eliminated the square roots. After simplifying i ended up with ax-bx/sqrt(x^2+ax)+sqrt(x^2+bx)...

help!

1.the only force acting on a 2kg body as it moves along the x-axis is given by F=(12-2x)N where x is in m. the velocity of the body at x=2m is 5.5i m/s. what is the maximum kinetic energy attained by the body? 2. KE= mv^2 3. My friend said the answer is 46J but I am not sure how...

1.the only force acting on a 2kg body as it moves along the x-axis is given by F=(12-2x)N where x is in m. the velocity of the body at x=2m is 5.5i m/s. what is the maximum kinetic energy attained by the body? 2. KE= mv^2 3. My friend said the answer is 46J but I am not sure how...