Recent content by chococho
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Finding the velocity of a proton at the surface of a conductor
Hm, I got 539444m/s... I guess I'm getting close? So I got -45 (at R=10) and -1500 (at R=0.3), I did -45-(-1500) and got 1455 for delta V. Then I multiplied by 1.6e-19 to get delta U, which equals delta K. Did I mess up again?- chococho
- Post #7
- Forum: Introductory Physics Homework Help
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Finding the velocity of a proton at the surface of a conductor
Are you saying find the potential at R=0.30m and at R=10m with -50nC as q for both of them to get delta V? And multiply by q again? Sorry, I'm a little confused.- chococho
- Post #5
- Forum: Introductory Physics Homework Help
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Finding the velocity of a proton at the surface of a conductor
yes. I set qΔV and 1/2mv2 equal to each other, and I used the potential I got for the sphere for ΔV. I'm really not sure how to go about doing this problem... but am I on the right track with "qΔV = 1/2mv2" to find the velocity? How do I get ΔV?- chococho
- Post #3
- Forum: Introductory Physics Homework Help
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Finding the velocity of a proton at the surface of a conductor
Homework Statement A charged conducting sphere with radius 30cm is having a charge of -50nC. A proton is released from rest at R= 10m. Calculate the velocity of the proton when it reaches the surface of the conductor. What happens to the velocity of the proton when the charge on the sphere...- chococho
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- Conductor Proton Surface Velocity
- Replies: 8
- Forum: Introductory Physics Homework Help
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High School Determining a charge at higher potential & potential energy
Hm, that's something we never learned in class.. Could you also explain the difference between what happens when you have a positive charge or a negative charge in the field?- chococho
- Post #3
- Forum: Electromagnetism
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High School Determining a charge at higher potential & potential energy
**sorry, the title should probably read determining a point at higher potential and potential energy So I feel like this is a really simple example, but I have a test tomorrow and this potential and potential energy stuff is really starting to not make sense... I know that a charge going in the...- chococho
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- Charge Energy Potential Potential energy
- Replies: 3
- Forum: Electromagnetism
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Three charged particles, finding the net force on each particle
When I said positive and negative, I was referring to the directions of the vector components of the forces. So my reasoning is that Q3 will move towards Q1 because they are opposite. I said this was F31 (Q3 due to Q1, I think). And I broke F31 down into vector components with x going to the...- chococho
- Post #5
- Forum: Introductory Physics Homework Help
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Three charged particles, finding the net force on each particle
Homework Statement Three charged particles are placed at the corners of an equilateral triangle of side 1.20 m (see figure). The charges are Q1 = +3.5 µC, Q2 = -7.2 µC, and Q3 = -5.1 µC. Calculate the magnitude and direction of the net force on each due to the other two. (Assume the +x axis...- chococho
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- Charged Charged particles Force Net Net force Particle Particles
- Replies: 6
- Forum: Introductory Physics Homework Help
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Total distance in simple harmonic motion
Yes I know that, but I just don't understand how 800A equals 16.- chococho
- Post #3
- Forum: Introductory Physics Homework Help
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Total distance in simple harmonic motion
Homework Statement A mass oscillates along the x-axis in simple harmonic motion. It goes through 200 cycles in 10 seconds and its vibrational amplitude is 0.020 m. What is the frequency, in hertz, and the total distance traveled, in meters, by the mass in the 200 cycles? Homework...- chococho
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- Harmonic Harmonic motion Motion Simple harmonic motion
- Replies: 3
- Forum: Introductory Physics Homework Help
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Finding the mass of a block after colliding with a spring
oh ok, I got the right answer. Thank you. So in the work energy theorem, is it always the case that kinetic energy is on one side of the equation and all the other energies are on the other?- chococho
- Post #5
- Forum: Introductory Physics Homework Help
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Finding the mass of a block after colliding with a spring
That is just Kf - Ki = W, correct? How would I add the spring energy and friction force?- chococho
- Post #3
- Forum: Introductory Physics Homework Help
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Finding the mass of a block after colliding with a spring
Homework Statement A block moves along a frictionless surface with an initial velocity of 10 m/s. It contacts a spring of spring constant 350 N/m. Underneath the spring at and after the point of contact the ground is rough and applies a constant friction force of 45 N. The spring compresses...- chococho
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- Block Mass Spring
- Replies: 5
- Forum: Introductory Physics Homework Help
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Finding coefficient of kinetic friction
OHHHH I got one of the signs wrong... Just making sure, so it's Fn = 100sin37 + mg? Because then I get 0.115 which should be right- chococho
- Post #9
- Forum: Introductory Physics Homework Help
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Finding coefficient of kinetic friction
So it's 100sin37 - Fn - mg = 0 ? When I solve for Fn I get 233.81. I solved for the forces in the x direction (ma = 100cos37 - Ffr) and I got Ffr to be 40.86. So do I just divide that by Fn to get the coefficient? It's still wrong, I'm confused- chococho
- Post #7
- Forum: Introductory Physics Homework Help