Recent content by chococho

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    Finding the velocity of a proton at the surface of a conductor

    Hm, I got 539444m/s... I guess I'm getting close? So I got -45 (at R=10) and -1500 (at R=0.3), I did -45-(-1500) and got 1455 for delta V. Then I multiplied by 1.6e-19 to get delta U, which equals delta K. Did I mess up again?
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    Finding the velocity of a proton at the surface of a conductor

    Are you saying find the potential at R=0.30m and at R=10m with -50nC as q for both of them to get delta V? And multiply by q again? Sorry, I'm a little confused.
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    Finding the velocity of a proton at the surface of a conductor

    yes. I set qΔV and 1/2mv2 equal to each other, and I used the potential I got for the sphere for ΔV. I'm really not sure how to go about doing this problem... but am I on the right track with "qΔV = 1/2mv2" to find the velocity? How do I get ΔV?
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    Finding the velocity of a proton at the surface of a conductor

    Homework Statement A charged conducting sphere with radius 30cm is having a charge of -50nC. A proton is released from rest at R= 10m. Calculate the velocity of the proton when it reaches the surface of the conductor. What happens to the velocity of the proton when the charge on the sphere...
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    Determining a charge at higher potential & potential energy

    Hm, that's something we never learned in class.. Could you also explain the difference between what happens when you have a positive charge or a negative charge in the field?
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    Determining a charge at higher potential & potential energy

    **sorry, the title should probably read determining a point at higher potential and potential energy So I feel like this is a really simple example, but I have a test tomorrow and this potential and potential energy stuff is really starting to not make sense... I know that a charge going in the...
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    Three charged particles, finding the net force on each particle

    When I said positive and negative, I was referring to the directions of the vector components of the forces. So my reasoning is that Q3 will move towards Q1 because they are opposite. I said this was F31 (Q3 due to Q1, I think). And I broke F31 down into vector components with x going to the...
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    Three charged particles, finding the net force on each particle

    Homework Statement Three charged particles are placed at the corners of an equilateral triangle of side 1.20 m (see figure). The charges are Q1 = +3.5 µC, Q2 = -7.2 µC, and Q3 = -5.1 µC. Calculate the magnitude and direction of the net force on each due to the other two. (Assume the +x axis...
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    Total distance in simple harmonic motion

    Yes I know that, but I just don't understand how 800A equals 16.
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    Total distance in simple harmonic motion

    Homework Statement A mass oscillates along the x-axis in simple harmonic motion. It goes through 200 cycles in 10 seconds and its vibrational amplitude is 0.020 m. What is the frequency, in hertz, and the total distance traveled, in meters, by the mass in the 200 cycles? Homework...
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    Finding the mass of a block after colliding with a spring

    oh ok, I got the right answer. Thank you. So in the work energy theorem, is it always the case that kinetic energy is on one side of the equation and all the other energies are on the other?
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    Finding the mass of a block after colliding with a spring

    That is just Kf - Ki = W, correct? How would I add the spring energy and friction force?
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    Finding the mass of a block after colliding with a spring

    Homework Statement A block moves along a frictionless surface with an initial velocity of 10 m/s. It contacts a spring of spring constant 350 N/m. Underneath the spring at and after the point of contact the ground is rough and applies a constant friction force of 45 N. The spring compresses...
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    Finding coefficient of kinetic friction

    OHHHH I got one of the signs wrong... Just making sure, so it's Fn = 100sin37 + mg? Because then I get 0.115 which should be right
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    Finding coefficient of kinetic friction

    So it's 100sin37 - Fn - mg = 0 ? When I solve for Fn I get 233.81. I solved for the forces in the x direction (ma = 100cos37 - Ffr) and I got Ffr to be 40.86. So do I just divide that by Fn to get the coefficient? It's still wrong, I'm confused
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