Determining a charge at higher potential & potential energy

AI Thread Summary
The discussion clarifies the relationship between electric potential (V) and potential energy (U), emphasizing that potential energy is calculated as U = qV, where q is the charge. A positive charge moving in an electric field goes from higher to lower potential, while a negative charge behaves oppositely, leading to confusion about their respective potential energies. In the provided diagrams, the potential at point B is higher than at point A, but the potential energy for a negative charge is greater at point A than at point B. The conversation suggests using "higher" and "lower" for potential and "greater" and "smaller" for potential energy to reduce confusion. Understanding these concepts is crucial for mastering the subject before the upcoming test.
chococho
Messages
20
Reaction score
0
**sorry, the title should probably read determining a point at higher potential and potential energy
So I feel like this is a really simple example, but I have a test tomorrow and this potential and potential energy stuff is really starting to not make sense...

I know that a charge going in the direction of the electric field goes from a higher potential to lower potential and from lower to higher if it's going in the opposite direction.
The problem is that I don't know how potential energy is different from potential.

So a diagram I have has two points A and B and an electric field going from right to left. There is also a positive charge just sitting between A and B. And it says PE for B is bigger than PE for A. Is this just because B is at a higher potential?

I also have a diagram that is the same, but only with a negative charge between A and B instead of a positive charge. This one I'm not really sure about.. I assumed it would be the opposite for a negative charge, but it says Vb is bigger than Va, but Ua is bigger than Ub.

Can somebody help me with this please? The more I think about it the more confusing it gets...
 
Physics news on Phys.org
If the potential is V, then the potential energy is qV.

That is, it needs to be multiplied by the charge. You can remember this easily if you are familiar with electron volts: eV. One eV is the energy acquired by an electron moving through a potential difference of 1 volt.
 
Hm, that's something we never learned in class..
Could you also explain the difference between what happens when you have a positive charge or a negative charge in the field?
 
chococho said:
I also have a diagram that is the same, but only with a negative charge between A and B instead of a positive charge.

Now you know that U = qV. If q is negative, what happens to U?

This one I'm not really sure about.. I assumed it would be the opposite for a negative charge, but it says Vb is bigger than Va, but Ua is bigger than Ub.

When you have a quantity that can be either positive or negative, it's less confusing to say "higher" instead of "bigger", and "lower" instead of "smaller". If Vb = (say) 5 volts, and Va = 3 volts, then Vb is higher than Va (Vb > Va).

However, if If Ub = -5 joules, and Ua = -3 joules, then Ub is lower than Ua (Ub < Ua).
 
I was using the Smith chart to determine the input impedance of a transmission line that has a reflection from the load. One can do this if one knows the characteristic impedance Zo, the degree of mismatch of the load ZL and the length of the transmission line in wavelengths. However, my question is: Consider the input impedance of a wave which appears back at the source after reflection from the load and has traveled for some fraction of a wavelength. The impedance of this wave as it...
Back
Top