Total distance in simple harmonic motion

AI Thread Summary
The discussion centers on calculating the total distance traveled by a mass in simple harmonic motion after completing 200 cycles. The frequency is determined to be 20 Hz based on the 200 cycles in 10 seconds. Each cycle involves the mass moving a distance of 4 times the amplitude, which is 0.020 m. Therefore, for 200 cycles, the total distance is calculated as 200 cycles multiplied by 4A, resulting in 16 meters. The calculation is clarified as 800 times the amplitude equals 16 meters.
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Homework Statement



A mass oscillates along the x-axis in simple harmonic motion. It goes through 200 cycles in 10 seconds and its vibrational amplitude is 0.020 m. What is the frequency, in hertz, and the total distance traveled, in meters, by the mass in the 200 cycles?


Homework Equations





The Attempt at a Solution



I got the frequency but cannot understand how to get the total distance.
The explanation just says "one cycle goes through distance 4A. 200 * 4A = 800A = 16m". Can someone explain this to me please?
 
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A is the Amplitude.
 
Yes I know that, but I just don't understand how 800A equals 16.
 
800*.02 = (8*100) * (2/100) = (100/100)*(8*2) = (1)*(16) = 16
 

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