Recent content by chunkytuna21

Which is more acidic, 4-nitrophenol or 2-fluoro-4-nitrophenol? I think it would be 2-fluoro-4-nitrophenol because acidity is increased by the presence of electron withdrawing groups. 2-fluoro-4-nitrophenol has two electron withdrawing groups as opposed to only one for 4-nitrophenol. Is that...

A high-torque dc motor designed to drive cassette decks has a no-load speed of 7400 rpm at 9 V with a torque of 9.6 in.·oz and a no-load current of 22 mA. How much power will it draw from a 8 V battery when turning freely? [Hint: At what voltage is it operating and how much current does it...

I didn't understand that at all. So I should draw something like this? And then the point is 23cm from the middle? ________________________<2.2A South______________ 28.28cm ________________________<2.2A...

Two long horizontal straight parallel wires are 28.28 cm apart and each carries a current of 2.2 A in the same direction, namely, due south. What is the B-field at a point that is a perpendicular distance of 23 cm from both wires? Answer in microtesla. B= (u0*I)/(2Pi*r) u0= 4Pi*10^-7=...

What do you mean? That is the equation for kinetic energy of the proton. I don't know the principle behind it.

A metal target sphere of 30 cm diameter suspended out in space is given a charge of +1.00 nC. Through what voltage must a distant proton be accelerated from rest (by some sort of space weapon) if it is to arrive at the sphere at a speed of 8.2*10^4 m/s? (Neglect any gravitational effects.)...

Great! Thanks.

An electron is initially at rest in a vacuum in a region where the potential is 0V. It is attracted by, and accelerates toward, a positively-charged metal plate at a potential of +12,000V. Assuming no other forces act on the electron, how fast is it moving when it hits the metal plate? Mass of...

What is the equivalent resistance of the circuit in Fig. P29 between terminals A and B? R1 = 5 , R2 = 5 , R3 = 5 and R4 = 1 . Note that the wires cross but do not make contact at the center. V= IRe IRe= IR1 +IR2 Series= Re= R1+R2 Parallel= 1/Re= 1/R1+R2 Re= R1R2/R1+R2 I am assuming...

Those are the correct numbers. I cut and pasted the question directly from my online hmwk and I'm looking at it right now. I don't think they've ever had a wrong answer, but I'll try it with 8.5 like the book. I only have one trial left anyway so I'm just going to wing it; I can live with a 93%...

Sorry, but I'm still not getting it. What do you mean by the 85000 and the seconds are supposed to be squared too? 85000^2/60^2? (1/2)(1.67*10^-27)(85000^2)(1.6*10^-19) + (8.99*10^9)(10^-9)/0.10= 89.9 And thanks for helping out physicsnoob93, but 95V isn't right either.

I got 59.93V, but that's incorrect. Maybe this will help. In my textbook the question is broken up into two parts. 35) A metal target sphere of 20cm diameter suspended out in space is given a charge of +1.00nC. How much work is done on a proton in taking it from very far away (essentially...

Ok, I only have three trials left so just to be clear: V= 1/2(1.67*10^-27kg)(82000m/s^2)+(8.99*10^9)(59.93V)(1.6*10^-19C)/0.15m Right?

Sorry, but you lost me with that. KE of what sphere? A proton? And what is e? In my first post, qe represents an electron volt according to my textbook. What does your e represent? If KE is for the proton, I would use KE= 1/2mv^2 right? Any other suggestions?

A metal target sphere of 30 cm diameter suspended out in space is given a charge of +1.00 nC. Through what voltage must a distant proton be accelerated from rest (by some sort of space weapon) if it is to arrive at the sphere at a speed of 8.2*10^4 m/s? (Neglect any gravitational effects.) V=...