Recent content by Clearik

Hmm, I see. The equation for moment of inertia at end of rod is Iend = mL2/3 Therefore, Iend = 1.33 kgm2 From my understanding of using the parallel axis theorem to calculate moment of inertia of a system, one would simply add up the inertias. Isystem = Icom + Iend of rod + Ipoint...

So perhaps; 2 x t rad/s = 3.16 rad/s t = 1.58 seconds? Does that make sense?

Oh, sorry, I forgot to add it, it's there now.

First off, I want to apologize for posting more than one question. I just discovered this site, so I wanted to check my work while I am able to. Thank you again. Homework Statement A massless rope of length L = 1 m is swung in the vertical plane, with a bob of mass m = 1 kg attached to its...

Homework Statement A pendulum is composed of a thin rod of length L = 50 cm, a moment of inertia of I = 0.2kgm2 with respect to its center and mass M = 400g. Attached to the bottom of the rod is a point mass (m = 200g). The pendulum swings in a vertical plane, attached by the top end to the...