Recent content by CogitoEAS

Thank you -I figured as much. I just have a professor who typically writes problems that aren't very tedious especially when you understand the concept(s). I saw a problem like this on an old exam and thought the busywork I had to do was a little uncharacteristic of his testing style. Thanks again.

Is there a quick way to figure out the total potential energy between more than 2 charges without having to find the potential at each point and the. Multiplying it by the charge at that point and adding it all up? For example - a 2D square with a charges Q, 2Q, -3Q, and another Q at each...

Thank you!

Yes, sorry, I've added the central question "What are the charges on the two capacitors?" to the original post. I'm also 100% sure I spelled FINDING right in the title but for some reason the d keeps getting changed to a g?!

Finding the charge on each capacitor in series Homework Statement In the circuit in the figure below, assume the resistance values are R1=1,400Ω and R2=2,500Ω, C1=55μF and C2=15μF, and the emf=5.5 V. The switch is labeled S. Consider the circuit in the figure below and assume the switch...

Sorry about that - this is actually my first post and I didn't realize you could add an attachment. I've attached an image of the circuit to this reply and the original post. Just so we're clear, you're suggesting that the voltage across the 3 ohm resistor is equal to the potential at point y?

Thanks for the reply! So if I want to calculate the potential at x I would add the potentials at both batteries and resistors 1 & 2? Or are you telling me to use ohms law at that point with the given current? In which case I don't know what the value for resistance would be at a junction

Also, I tried to edit the title to read "Find" but I guess it won't update.....don't judge me

Hello, I'm wondering how to determine the value of the potential difference between two points (junctions specifically) in a circuit with 2 emfs. The junctions are points x and y in the circuit below. I thought I could use the junction rule to determine the current at each junction...