Yes, I am with you so far.
In typing this response, I seem to have neglected the observation that I am taking the limit from the right and that All Students Take Calculus... aka tan (pi/2 + 0.01) < 0 (where 0.01 is some very small positive number)! Which of course is negative.
Sometimes I...
Okay, what you say makes sense, but how do I know which it is?
When I look at the graph of f(x)=cos x, I can understand how it can yield a negative value. What I don't understand is how, from the equation I am finding the limit of, how can I determine that a -1 is still hanging around?
Is...
Forgive me, but if the negatives canceled out, how do I know to 'move the -1' around?
I realize that tan x is undefined and that it tells you it's one of the infinities, but doesn't tell you which... from that I concluded that because the -1 canceled out, the resulting limit would be positive...
But it's not -sin x... the negatives canceled out...
lim [x->pi/2]+ of -sinx / -cosx leaves a positive (the -1 cancels out)
I don't understand. Even if (pi/2) is slightly bigger (as approaching from right), then sin x still goes to 1, not -1.
I don't mean to be difficult; I wish to...
SOLVED, thanks to Dick and viciousp!
Homework Statement
The question asks: Find the limit. Use L'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. If L'Hospital's Rule doesn't apply, explain why.
Limit as x approaches pi/2 from the right (+) of...
Ohhhh, okay, I think I get what you're saying. Because I canceled out the sin x term and not just factored it, I lost it; same idea as solving for x -> (x+2)(x+4)=0 ; x=-2 or -4; in this example I divided out the (x+4) and only arrived that x=-2, ignoring the (x+4), which I can't forget...
jhicks... not sure what you're getting at. Here's what I did when I said I "Rearranged and canceled" terms:
sin x = sin x / cos x (because tan x = sin x / cos x)
sin x * cos x = sin x (multiply both sides by cos x)
cos x = sin x / sin x (divide both sides by sin x)
cos x = 1...
SOLVED! Thank-you jhicks and Tedjn!
I am taking a basic calculus course and have some weaknesses when it comes to trigonometry. In this case, it's pure trig.
Homework Statement
The question states: "Find all values of x in the interval [0,2pi] that satisfy the equation sin x = tan x"...
1. Homework Statement :
The question asks to find the limit as x approaches 8 of (2x^2 - 3x + 4).
So I use the limit law/property which states that if f is a polynomial or rational function and if a is in the domain of f, then the limit of f(x) as x approaches a is f(a). Correct?
2...