Recent content by crimsondarkn

Oh I just fixed that but then I found out the real problem... The Else statement I had cause the program to output nothing since it always broke out of my loop. Thx for help

Let's say I input MOO the output would be NPP N is after M P is after O I tried with Caps, does the same thing

Here's what I wrote , but there's no output.. It is suppose to read a line typed from the user and enter whatever the input was with the letter after the ones inputted. please help import java.util.Scanner; class ProblemS2 { static Scanner sc=new Scanner(System.in); public static...

Homework Statement What values of n are involved in the transition that gives the rise to the emission of a 388-nm photon from hydrogen gas? Homework Equations n=? wavelength = 388nm=3.88x10^-7 m R=1.097x10^7 m^-1 E= hc/ wavelength The Attempt at a Solution E= hc/...

Okay, I've done all the calculations but one doesn't give me the right answer... I'm not sure if its the book's error so if u guys could check please.. Three possible transactions: (7.22-4.82) , (7.22-6.41), (6.41-4.82) wavelength 1 = hc/Ef-Ei = (6.63x10^-34)(3.00x10^8) /...

I solved a, but I couldn't figure out b... I've tried different combinations but nothing turned out correctly... Homework Statement The emission spectrum of an unknown substance contains lines with the wavelengths 172 nm, 194 nm , and 258 nm, all resulting from transitions to the ground...

Why are Absorption lines dark? I don't really understand the spectroscope and how it works... Can anyone help me out with this theoretical question? No math involved! Thanks.

turns out the book was wrong... my answer was right. yah...

Homework Statement This is a pretty simple problem... Yet I got the wrong answer.. Hmm... "Find the threshold frequency for a calcium surface whose work function is 3.33eV" W=3.33eV = 3.33eV * 1.6x10^-19 J = 5.33x10^19 J f = ? h=6.63x10^-34 J*S Homework Equations f=W/h The Attempt at a...

Yeah...this is an incredibly easy physics question , you're stressing too much over it.

I'm stuck on part c now... Calculus the change in total kinetic energy of the system at minimum separation. Here's my work v'=-0.6m/s 1/2m1v1^2 + 1/2m2v2^2 = 1/2m1v1'^2+1/2m2v2'^2 cross out all the 1/2s and also v2 becomes zero m1v1^2 = m1v1'^2 + m2v2'^2 (2.4)(-1.5)^2 =...

Oh I got it, thanks! This is what I did.. m1v1+m2v2=m1v'1+m2v'2 m2v2 becomes zero since its stationary m1v1=v'(m1+m2) -3.6=v'(6) v'=-3.6/6 v'= -0.6 m/s ---> 0.6m/s[W] I didn't know it was completely elastic collision, that's why I was stuck.

A 2.4 kg dynamics cart with a linear elastic spring attached to its front end is moving at 1.5 m/s [W] when it collides head on with a stationary 3.6 kg cart. What is the velocity of each cart at minimum separation? The answer is 0.6 m/s [W] Can anyone show me the steps?