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I calculated like this. I want to make 3 % of starch so I weigh 3 gram of starch. Then 5 % of citric acid which is 1.28 gram then catalyst 50 % which becomes 0.64 gram. Then I will add 96.23 gram of water. Am I right?

Homework Statement In the materrials and methods of one article is mentioned that: A specific amount of citric acid and the catalyst sodium hypophosphite (50 % w/w, on weight of citric acid used) was dissolved in the starch solution. My question is how much citric acid and sodium...

Homework Statement Before, I started to evaporate my solvent (butanol) by using rotary evaporator, I greased the ground glass joint holding my flask and bump trapper. Subsequently, I secured my flask sample and the trapper with Keck clip . Is there any possibility that my sample may have been...

I want sorbitol to be 30% of the total amount. So if I have 70 % starch I have 4.6 g and if I want to have 100 % then how much starch it would be which becomes 6.5. X=4.6*100/70= 6.57 Then I deducted 6.5 from 4.6 which it becomes 6.5-4.6=1.97 gram of sorbitol should be added to the starch. Is...

I want to add 30 % sorbitol to my starch. Therefore, I calculated like below. starch starch 70 100 4.6 X X=4.6*100/70= 6.50 g. So, amount of sorbitol needed is 6.5-4.6=1.96 g But If I do like your way X=4.6 * 0.3=1.38 gram Now I have got...

yes I meant xylan as my starch and I want sorbitol to be 30% of the total amount.

Homework Statement I have 4.6 gram of starch and I want to add 30 % of sorbitol to xylan. How much gram of sorbitol, should I weigh on the balance? Homework EquationsThe Attempt at a Solution

Solid phase seperation?

So, what is the solution? Do you have any idea?

Hi, I didnt understand what do you mean? Starch is not soluble neither in water nor in ethanol but lipids are soluble in organinc solvent such as chloroform. But the problem is starch would be precipitated under all the solvents (it would be water phase,organic phase and the. Precipated...

Homework Statement I want to extract and quantify lipids inside the starch. Which solvents you recommend for the extraction? Homework EquationsThe Attempt at a Solution

Now I understood. Initial amount of starch was 230 mutiple 0.03=6.9 gram therefore the concentration is 6.9/130=5.3 % Am i right?

Yes it was only water evaporated and removed. The % concentration is based on gram of starch divided to gram of all the materials (Starch+water). In this example 3.9 gram starch remained and the total gram of material left is 130 gram. So, 3.9/130=3 %. But, I get confused why I get again 3 %...

But I don't know what should I do after this. Could you please help me.