Recent content by Decadohedron

There would be the parallel component in the r direction mω2rcos2(Φ) + the perpendicular component mω2rsin(Φ)cos(Φ)

So I should be using mr'' = -GMm/r2 + mω2r instead and solve the PDE and go from there?

Homework Statement A bead slides along a frictionless wire which lies in the N/S direction, midpoint at the equator. All points along the wire are the same distance from the center of the earth. The bead is initially at rest then released a small distance, δ, to the north of the equator...

Thanks for the clarification dudes! Now what's the integral of 2x *ponders* The internet needs sarcasm font.

It does, because it's a simple integral, but that's not where the confusion lies... From the prof's mouth: "Both the Divergence AND the Curl of an E field must be 0 for a field to be Electrostatic" Then, to me, if the divergence isn't 0 -> not electrostatic -> no need to do the following, since...

Which should mean that I can be at some random r far away from the charge density and it's not an electrostatic field.

Homework Statement Given an E field, determine if it's a possible electrostatic field. If so, determine a potential Homework Equations ∇⋅E ∇×E The Attempt at a Solution [/B] Just more of a clarification, since my friend and I both attempted this question differently. I took the...

Homework Statement Suppose that { |ψ1>, |ψ2>,...,|ψn>} is an orthonormal basis set and all of the basis vectors are eigenvectors of the operator Q with Q|ψj> = qj|ψj> for all j = 1...n. A particle is in the state |Φ>. Show that for this particle the expectation value of <Q> is ∑j=1nqj |<Φ|...

It would be that easy... Thanks a lot.

Homework Statement A thin infinite wire with linear charge density λ is located parallel to an infinite conducting surface, which is coincident with the x-y plane (i.e., z = 0). The wire is parallel to the ˆx direction and is located a distance z = d from the conducting surface. The figure on...

There was no other y in the expression so I figured it'd be safe to Taylor expand then. Glad I finally got this - thanks to you guys! My head was getting sore from beating it on the desk so much. Now onto part b

I"m not quite sure what you mean by construct here, so I assumed this rsin theta = y sin theta = y/sqrt(d^2+y^2) So then I taylor expanded 1/sqrt(d^2+y^2) and since it's to the highest order of y, I ended up with sin theta approximately equals y/dWhich when I put that back into the original...

r sin theta would give me that magnitude of y? I really appreciate the help guys - sorry that I"m being a bit dense at the moment.

I should have called it something else but ##\hat{r}## = rvector/|r| = (0, y)/sqrt(x^2+y^2)

I"m supposed to calculate the force once it's shifted in delta y. https://drive.google.com/open?id=0B76TBRMyBuffbkVPY3hjZU0xV3M The picture above is where I always get to before not knowing what to do anymore.