Recent content by Doom of Doom
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Graduate Light emitting diodes and Planck's Constant
This image is a good reference.- Doom of Doom
- Post #2
- Forum: Atomic and Condensed Matter
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Graduate Light emitting diodes and Planck's Constant
In my lab class we performed an experiment, in which we 'determined' the value of Planck's constant (value of h/e actually) by measuring the turn-on voltage for light emitting diodes of various colors. The idea is: Given a light emitting diode that emits light with a maximum wavelength of...- Doom of Doom
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- Constant Diodes Light
- Replies: 1
- Forum: Atomic and Condensed Matter
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Mathematica Mathematica Export to PDF problem
Hello, I am also having an export problem in Mathematica when trying to export pdf format. Namely, I can't get it to export pdf images at all! Anything I try to export, such as the image: sinplot=Plot[Sin[x],{x,0,1}] will export perfectly fine to .jpg or .png file types...- Doom of Doom
- Post #6
- Forum: MATLAB, Maple, Mathematica, LaTeX
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Abstract Algebra: Extension Fields & Complex nth Roots
Ok, for 2), I've got the formula \left[\mathbb{Q}\left(e^{ik\pi/n}\right) \, : \, \mathbb{Q} \right] = \phi\left(\frac{n}{\gcd(n,k)}\right) , where phi is Euler's totient funciton. Is that right? Now I just have to prove it...- Doom of Doom
- Post #3
- Forum: Calculus and Beyond Homework Help
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Abstract Algebra: Extension Fields & Complex nth Roots
Two problems from my abstract algebra class... 1) Let K be the algebraic closure of a field F and suppose E is a field such that F F \subseteq E \subseteq K. Then is K the algebraic closure of E? 2) Let n be a natural number with n\geq2, and suppose that \omega is a complex nth...- Doom of Doom
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- Extension Fields
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Graduate Strongly connected primitive matrix
Ok, I thought about it a little more. Hn-1 might not necessarily be positive, since it might not be possible to go from i to j in exactly n-1 steps, but it would be possible for some k, 1<k<n-1. Also, the diagonal entries of Hn-1 would not necessarily be positive (if for some node you have to...- Doom of Doom
- Post #2
- Forum: Linear and Abstract Algebra
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Graduate Strongly connected primitive matrix
If H is a nxn primitive, irreducible matrix, is it always true that Hn-1 > 0? That is, every entry in Hn-1 is positive. From my class notes, the definition of H primitive is that there exists some k>0 such that Hk > 0. And a matrix is irreducible if its digraph is strongly connected (that...- Doom of Doom
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- Matrix Primitive
- Replies: 1
- Forum: Linear and Abstract Algebra
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So, my question is, where did I go wrong in my approach?
Ok, I'm started off with a different approach to see if I could understand this a bit better... and it only leads me to believe that the problem must be wrong. ---- Assume K=1 (since that is the smallest it can be). Then S is the set of functions on [0,1] such that |f(x)| < ||f|| for all x in...- Doom of Doom
- Post #6
- Forum: Calculus and Beyond Homework Help
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So, my question is, where did I go wrong in my approach?
Still at a loss... So: Assume {u1, ..., um} is an orthonormal basis of S. I'm trying the function f= u1 + ... + um. Is this the right one to consider? It certainly is the nicest. Then ||f|| = sqrt(m). I still don't know where exactly to apply the Bessels inequality. If I do, all I keep...- Doom of Doom
- Post #4
- Forum: Calculus and Beyond Homework Help
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So, my question is, where did I go wrong in my approach?
Let S be a subspace of L^{2}(\left[0,1\right]) and suppose \left|f(x)\right|\leq K \left\| f \right\| for all f in S. Show that the dimension of S is at most K^{2} --------- The prof hinted us to use Bessel's inequality. Namely, let \left\{ u_1,\dots, u_m \right\} be a set of...- Doom of Doom
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- Finite L2 Subspace
- Replies: 5
- Forum: Calculus and Beyond Homework Help
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Schools Do Graduate Schools Look at Extra Curiccular Involvement In Admissions?
Last year, I was also a homework grader and tutor for Calculus 2. I'll probably put them in my application, alongside my 6 semesters of research. Also, I really love to teach, and I really want to be a professor mostly because theoretical physics is interesting to me and beable to teach it...- Doom of Doom
- Post #18
- Forum: STEM Academic Advising
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Schools Do Graduate Schools Look at Extra Curiccular Involvement In Admissions?
I am the president of the SPS at my school, and we organize tutoring sessions for the intro level physics classes. So, I volunteer 4 hours a week to tutor college physics. Also, I volunteer at a local high school to tutor math. Do these kind of "volunteering extracurricular activities" help...- Doom of Doom
- Post #15
- Forum: STEM Academic Advising
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Depth of an eigen value (generalized eigenspaces)
Let A be a matrix and \mu be an eigenvalue of that matrix. Suppose that for some k, \tex{ker}\left(A-\mu I\right)^k=\tex{ker}\left(A-\mu I\right)^{k+1}. Then show that \tex{ker}\left(A-\mu I\right)^{k+r}=\tex{ker}\left(A-\mu I\right)^{k+r+1} for all r\geq0.- Doom of Doom
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- Depth Value
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Normal operators with real eigenvalues are self-adjoint
Prove that a normal operator with real eigenvalues is self-adjoint Seems like a simple proof, but I can't seem to get it. My attempt: We know that a normal operator can be diagonalized, and has a complete orthonormal set of eigenvectors. Let A be normal. Then A= UDU* for some...- Doom of Doom
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- Eigenvalues Normal Operators
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Sequences of Lipschitz Functions
Hmm.. after a bit more thinking... I think that the sequence only needs to converge pointwise (not uniformly) to a function in order for the limit function to also be in LipC([a,b]). So, my proof for (i) pretty much works. (I think) Please tell me if I am wrong?! Also, interestingly, I...- Doom of Doom
- Post #2
- Forum: Calculus and Beyond Homework Help