Recent content by dreamspace

Homework Statement So the problem revolves around a Linear Electric Quadrupole, with two positive charges on z-axis (in positions s and -s from origo) and two negative charges in origo. 1. Show that potential from a position R can be written as 2. The quadrupole moment can be...

This is not homework, but rather me just trying to work a numerical analysis problem. I have a second order equation on the form m*y'' = a*y + n*x (no first derivative) How does one convert this? It's been years since I did this. Last I remember, one would start with substituting the...

Homework Statement Homework Equations The Attempt at a Solution Here's what I've tried so far, not really sure how to go on with these problems. Been reading the textbook up and down on Poisson processes! Any hints or help? Especially 1.B, 1.C and 2.B, 2.C

Thanks. Yes, now I understand the problem. But alas, I'm still not sure how the set it up. I'm understanding (correctly?) that the U vector will be the approximate solutions for the Diff. EQ Let's take the case of N=4 , would the Matrix equation look like this: n^{2} \begin{pmatrix}...

Hi Yes, I can solve the Differential Equation by hand, and I have some limited knowledge/experience with LU factorization, Gauss-Seidel etc. And matrices in general, but it kinda stops there. I have in general problems understanding how to use everything for the problem, and some of the info...

Homework Statement Homework Equations Not sure. The Attempt at a Solution Have no idea, as I don't have any/much previous experience with Linear Algebra. Can anyone help me with starting on this, hints/tips?

After doing some reading, this looks like something that falls under Geometric Distribution. Correct?

Homework Statement Suppose that I'm collecting cards, and that in a complete collection there are m items. When buying a new card, there's an equal probability that the card is any of those m cards. Let X be the number of cards I need to buy in order to get a complete collection...

I = \frac{E}{R} = \frac{4V}{Ri+(R1||R2||R3)} = \frac{4V}{2 ohm + (\frac{1}{4 ohm}+\frac{1}{6 ohm}+\frac{1}{12 ohm})} = \frac{4V}{2 ohm} = 2A

Hey, first of all, I'd start with finding the Main current I. The 2 ohm(R2), 2 ohm(R3) and 4 ohm(R4) resistors are all in parallell with each other, and in serial with the 3 ohm (R1), so: R1 + (R2||R3||R4) = Rtot 3 ohm + ((1/2 ohm)+(1/2 ohm)+(1/4 ohm)) = 3.8 ohm You'll find the...