Recent content by duggielanger

This question is off my forum , and I was just wondering if anybody could help. I don't understand why -1/2 is the higher energy level and +1/2 is the lower energy level. For spin state -1/2, if the external magentic field B0 and magnetic moment uZ oppose each other, surely the energy...

Ah right think I have it now , multiply by the least common denominator, which is 5, which leaves me with -x^2+x-30=0 and the by -1 to get x^2-x-30=0 and then factor to get (x+5)(x-6). Thank you everyone

yeah thank you for that i will remember the minus sign

Not answered the question yet ,and not done them yet they are coming up in the section. Will try and find the answer in a bit and post my results .

Homework Statement Use algebra to find the x-intercepts and y-intercept of The graph of y=-x^2/5+x/5+6 this is a parabola. Homework Equations y=-x^2/5+x/5+6The Attempt at a Solution Find the y-intercept , which is substitute 0=x into the equation to find the answer , done that . The problem...

Thank you very much I have now , its taken two days for that to sink in !

Yeah getting that wrong about Etrans, just looked at my textbooks and was reading it wrong . I have an asnwwer for the last bit not sure if rights but this is what I have for that. 24/25 x 3.00 x10^8 =2.88000 x 10^8 ? So are you saying just add the values for a proton = 1.67 x 10^-27 the...

Homework Statement The mass of a proton when at rest is m. According to an observer using the detector frame, the speed of the anticlockwise moving bunch, A, is such that va^2/c^2=24/25 Show that the total relativistic energy of a proton in bunch A, as observed in the detector frame, is...

Thank cepheid just quickly revised my answer as it was positive , even though I knew it should be negative. Thats what tiredness can do to you . THANKS FOR THE HELP

Will it be negative

Ah so is it q*E=m*g as these are the two forces acting on the drop and since I want q I make this the subject and now we have q=m*g/E

Its similar to the millikan Experiment I think the Net force will be zero There will be two forces acting on the droplet and both contribute to the net Force

Hi cepheid that's what I meant for equation two just couldn't think how to put it down. Yes it is uniform electric field. So is my workings out for F=mg ok and do I now need to find E=V/d for the electric field and then use this to find the charge on the raindrop at a point in space .

Homework Statement Two parallel plates are placed 0.10 m apart with one vertically above the other and their edges aligned. The potential difference of the upper plate is 100 kV relative to the lower plate. What charge must a spherical raindrop of diameter 1.0 mm carry if it remains...

Ok thanks A lot SammyS your help is appreciated