Recent content by eanderson

A 50.5-g golf ball is driven from the tee with an initial speed of 40.4 m/s and rises to a height of 26.5 m. (a) Neglect air resistance and determine the kinetic energy of the ball at its highest point. (b) What is its speed when it is 6.02 m below its highest point? A: 28.0838075 J b: ...

the answer for those numbers is: A: 6143292.682926829 J B: 1466.846 Calories

Bicyclists in the Tour de France do enormous amounts of work during a race. For example, the average power per kilogram generated by Lance Armstrong (m = 75.0 kg) is 6.50 W per kilogram of his body mass. (a) How much work does he do during a 155-km race in which his average speed is 12.3 m/s...

what do i do now?

wouldnt kinetic be 0 at the highest point because all the energy is potential?

.0477(-9.8)(31.2) = -14.584752

U=mgh... 47.7(-9.8)31.2 =14584.754 = U or gravitational potential energy

Fk = ukN...

K = (1/2)mv^2 and i need something to help deal with the height part

A 47.7-g golf ball is driven from the tee with an initial speed of 55.4 m/s and rises to a height of 31.2 m. (a) Neglect air resistance and determine the kinetic energy of the ball at its highest point. (b) What is its speed when it is 8.47 m below its highest point?

A 109-kg crate is being pushed across a horizontal floor by a force P that makes an angle of 38.3 ° below the horizontal. The coefficient of kinetic friction is 0.260. What should be the magnitude of P, so that the net work done by it and the kinetic frictional force is zero?

sweet thanks for your help

so my ratio answer is no units then right?

Fnet = mv2/r = 252^2/616 = 103.090909 Fn = Fnet + mg = 103.090909 + 9.8 = 112.890909? Fn/mg? 112.890909/9.8 = 11.5 = the ratio?

F = mv^2/r = m252^2/616 = 103.090909 that's excluding m... f=ma = 103.090909??