Calculating Kinetic Energy: Golf Ball with Initial Speed of 55.4 m/s

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A 47.7-g golf ball is hit with an initial speed of 55.4 m/s and reaches a height of 31.2 m. To find the kinetic energy at its highest point, the conservation of mechanical energy principle is applied, where kinetic energy (KE) and potential energy (PE) are balanced. At the highest point, the ball's vertical velocity is zero, but it retains horizontal motion, meaning it still has kinetic energy. When calculating the speed at 8.47 m below the highest point, both KE and PE must be considered, as the ball loses KE while gaining PE. The discussion emphasizes careful unit conversion and the application of relevant equations for accurate results.
eanderson
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A 47.7-g golf ball is driven from the tee with an initial speed of 55.4 m/s and rises to a height of 31.2 m. (a) Neglect air resistance and determine the kinetic energy of the ball at its highest point. (b) What is its speed when it is 8.47 m below its highest point?
 
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What have you tried? You need to show some effort. What equations/concepts might apply here?
 
K = (1/2)mv^2 and i need something to help deal with the height part
 
Do you know about gravitational potential energy?
 
U=mgh... 47.7(-9.8)31.2 =14584.754 = U or gravitational potential energy
 
Mechanical energy (KE + PE) is conserved. Careful with units. (The mass is given in grams, not kg.)
 
.0477(-9.8)(31.2) = -14.584752
 
wouldnt kinetic be 0 at the highest point because all the energy is potential?
 
eanderson said:
wouldnt kinetic be 0 at the highest point because all the energy is potential?
No. Only the vertical component of velocity is zero at the highest point--it's still moving horizontally.
 
  • #10
what do i do now?
 
  • #11
eanderson said:
what do i do now?
Compare the initial energy (KE + PE) at the start with the energy (KE + PE) at the top. The ball loses KE as it gains PE.
 
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