Kinetic Fictional Force help please

Thread starter eanderson
Start date Oct 4, 2007
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Force Kinetic

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To achieve zero net work done by the force P and the kinetic frictional force on a 109-kg crate, the magnitude of P must counteract the frictional force while considering the angle of application. The coefficient of kinetic friction is 0.260, which affects the normal force and, consequently, the frictional force. The work done by force P over a horizontal distance d must equal the work done against kinetic friction. Calculating the normal force involves adjusting for the vertical component of P due to its angle of application. Ultimately, the correct magnitude of P ensures that the total work done is balanced, resulting in no net work.

Oct 4, 2007

eanderson

A 109-kg crate is being pushed across a horizontal floor by a force P that makes an angle of 38.3 ° below the horizontal. The coefficient of kinetic friction is 0.260. What should be the magnitude of P, so that the net work done by it and the kinetic frictional force is zero?

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Oct 4, 2007

eanderson

Fk = ukN...

Oct 4, 2007

learningphysics

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Suppose the box travels a distance d horizontally... then what is the work done by the force P ?

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