Yes,
$$(1,0)\otimes (1,0) + (0,1)\otimes (0,1) = \sum_{j1,j2=1}^2 \beta_{j1,j2} b_{j1}^1\otimes b_{j2}^2$$
where ##b_1^{1,2}=(1,0), b_2^{1,2} = (0,1)##, ##b^k_{jk} \in V_k## and ##\beta_{1,1}=\beta_{2,2}=1 ; \beta_{1,2}=\beta_{2,1}=0##. To represent this functional as a tensor product of...