Recent content by EvilBunny

As for trig sub i come down to S 1/(U² * sqrt(U-9) ) which would mean my hypotenus is sqrt(U) and i will have one side 3 and the other sqrt( U-9) ? right I just never dealt with sqrtU as a side until today

(Ax + B)/(9 + x^2) + (Cx + D)/(9 + x^2)^2 [ (Ax + B)(9+x^2) + (Cx +D ) ] / ( 9 + x^2 ) ^2 = 1/(9+x^2)^2 (Ax + B)(9+x^2) + (Cx +D ) = 1 9Ax + Ax^3 + 9B + B^2 + Cx + D = 1 Ax^3 + Bx^2 + (9A +C )x + 9B + D = 1 A=0 , B=0 , C=0 , D=1 1/(9+x^2) ^ 2 ?? did i do something...

Evaluate this indefinite integreal S = integral S 1/(9+x^2)^2 This has been driving me and my friend nuts. We tried partial fractions only to realize that it brings us back to the same thing because its not a polynomial over a polynomial, we tried by parts and it did not help and we...

Okay thanks for your replies the teacher said my answer is reasonable. I had 52 because of signaficative figures and a bunch of roundings. As for the low molar mass the teacher said its an acid you wouldn't know . So something obscure and uncommon or something of the sort

(purpose is to find molar mass) At the start we dissolved 0.945 grams of unknown weak acid into water and made it up to 100 ml Then we used 25 ml of that solution and titrated it until the end point. Now , this is a monoprotic acid so it's going to take 1 mol of acid to neutralise 1 mol of...

Homework Statement A 150 grams particle oscillating in SHM travels 24 cm between the two extreme points in its motion with an average speed of 60cm/s Find a) angular frequency b) the maximum force on the particle C) the maximum speed The Attempt at a Solution My first...

Well I'd go with kinetic friction. As its asking me to find the acceleration , but it could be possible its 0 so I could verify if the force on the block is bigger then Fs which would mean it would slide , which would mean its kinetic only. Well I got it I think. Thank you

Homework Statement A 2.5 kg block is on a 53 degres incline for which Uk = 0.25 and Us = 0.5 . Find its acceleration given that (a) it is initially at rest. I don't know how to approach this. We have kinetic friction when an object slides. This object starts at rest. Does that mean...

lim as x goes closer to minus infinity. x^4 + x^5 now visibly the answer is minus infinity since the equation are simple. But aside from saying x^5 is bigger then x^4 could there be anything else to do ?

Homework Statement I need to find a tangent line equation but my main problem is isolating actually. sqrt ( 2x + 2y ) + sqrt ( 3xy) = 13 The Attempt at a Solution 0.5 ( 2x + 2y ) ^ -0.5 (2+2y') + 0.5(3xy) ^ -0.5 ( 3 ( y + y' x ) ) = 0 this is where I get stuck

Neat I get it, thanks.

Homework Statement Let arctan (\sqrt{3x^2 -1}) then dy/dx Well I know that the derivative of arctanx is 1/ 1 + x ² but when I got something other then simply x I don't know how to proceed

K managed to get it off of that thx

Homework Statement If f(x) = (3 x )(sin x) (cos x), find f'( x ). A question I have is , is there anything special to do when you have 3 products instead of 2 The Attempt at a Solution Well I used the product rule as if am multipling (3xsinx) (cosx) but that doesn't...

My teacher does like putting in nasty problems sometimes tho. Maybe that's it ? sometimes he writes soemthing partlially and says you will know how next week.