Recent content by FabledIntg

Great, thank you for your help sir!

Perfect! I understand now! One last thing, why did you choose to have the force negative? Is it simply because the x-axis is negative if going to the left, and y-axis negative if going down?

But I'm essentially multiplying r*dθ*L with P0*cos^2(θ), and then integrating from 0 to π. Can you explain why I have to do this multiplication? What does it mean in a physical sense? Multiplying an infinitesimal area with a force.

Ah, I see now. That should be r*dθ. The x-component of P is Px = P0*cos2(θ). Do I now need to sum all of these x-components?

I really don't see how the area is clearly r*dθ*dz. I suppose you're referring to the surface area of the body, and not the side where the windows of the hut are. If I choose an are that is generated by going from θ to dθ, The surface area is the circumference from θ and dθ multiplied by the...

Okay thanks for your answers. But we haven't learned parametrisation of surfaces yet. Is there another way of solving this problem with rectangular coordinates?

So what is $d\vec{S}$? How do you go from $d\vec{S}$ to $d\theta$? Seems LaTeX doesn't work like this.

The problem is to determine the shearforce Q on the hut near the ground. This is not a homework or anything like that, I'm just studying for an exam and this problem is in the book "Engineering Mechanics, Statics" By Meriam Kraige. On another forum, I found this: I understand the part in...

Ok, but as I understand, F1 can't be divided into vertical/horixontal components since it's already pointing straigt downwards, so it has only one vertical component. For F2 I get F2y = F2 cos(α) F2x = F2 sin(α) So I get R = F1 + F2y + F2x = F1 + F2 cos(α) + F2 sin(α). Still wrong. Keep in...

Yes I understand that, and I've tried the answer 0, but is still says it's wrong answer. However, if the moment doesn't contribute an external force, shouldn't the resulting force of F1 and F2 be just R = F1 + F2? I don't understand How I'm supposed to express a resulting force with all those...

Hi, Problem: Express the resultant force in terms of F1, F2, r, t and α.

I'm supposed to express the reultant force R of M, F1 and F2 in terms of F1, F2, r, s and α. But I need to know how to draw R first. How can one do this? Does the couple create a force uppwards from O? Can I move F_1 and F_2 also to the origin and combine the forces? Here is the image:

So how should I set up my calculations so I get the correct answer right away? I'd never figure this out if it was a real test.

Can you point out exactly where I did this? Because if you look at the attachment for the problem, it clearly shows that h is the height from the bottom of the loop and not the top. I simply expressed h in terms of a.

Oh, I see. I suppose I should just add h = 2a + \frac{a}{2} = \frac{5}{2}a. But how did you know that my answer is from the top of the loop and not from the bottom?