How can I draw the resultant force of the couple M, F1 and F2?

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To draw the resultant force R of the couple M, F1, and F2, one must resolve the forces into their horizontal and vertical components. The moment M does not contribute an external force, so the resultant force should be expressed as R = F1 + F2y + F2x, where F2y and F2x are the vertical and horizontal components of F2, respectively. It is important to note that F1 is purely vertical, while F2 can be broken down using trigonometric identities based on angle α. The discussion emphasizes the need for a clear understanding of vector resolution to accurately express the resultant force using the given variables. Properly determining the components of R is essential for solving the problem correctly.
FabledIntg
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I'm supposed to express the reultant force R of M, F1 and F2 in terms of F1, F2, r, s and α. But I need to know how to draw R first. How can one do this?

Does the couple create a force uppwards from O? Can I move F_1 and F_2 also to the origin and combine the forces?

Here is the image:

qygwsn.png
 

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What is the exact statement of the problem?
 
Hi,

Problem: Express the resultant force in terms of F1, F2, r, t and α.
 
So you are aware that, for a rigid body to be in equilibrium, the sum of the forces and of the moments acting on the body must each be zero, right? The moment M does not contribute an external force.
 
Yes I understand that, and I've tried the answer 0, but is still says it's wrong answer.

However, if the moment doesn't contribute an external force, shouldn't the resulting force of F1 and F2 be just R = F1 + F2? I don't understand How I'm supposed to express a resulting force with all those variables. I've tried similar triangles and all sorts of trig identities.
 
FabledIntg said:
Yes I understand that, and I've tried the answer 0, but is still says it's wrong answer.

However, if the moment doesn't contribute an external force, shouldn't the resulting force of F1 and F2 be just R = F1 + F2? I don't understand How I'm supposed to express a resulting force with all those variables. I've tried similar triangles and all sorts of trig identities.
Vectorially, R = F1+ F2. But, to sum these forces, you need to resolve them into horizontal and vertical components, and then add the components. R has a component in the horizontal direction and a component in the vertical direction. If you have tried to do this, please show us what you have done.
 
Ok, but as I understand, F1 can't be divided into vertical/horixontal components since it's already pointing straigt downwards, so it has only one vertical component. For F2 I get

F2y = F2 cos(α)
F2x = F2 sin(α)

So I get R = F1 + F2y + F2x = F1 + F2 cos(α) + F2 sin(α).

Still wrong. Keep in mind that it's not nesseccary to use ALL the variables above in order to express R.
 
This is not done correctly. You seem to lack the knowledge of how to get the components of R and then to determine its magnitude. Have you been taught how to do this kind of thing in your course?
 
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