Recent content by fal01

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    Find Change in the Electric Potential

    Thanks! I was just missing the negative sign.
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    Find Change in the Electric Potential

    so what I started doing was right... (40000V/m)(.3m) =12000 V when I put in that answer it says I am wrong :(
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    Find Change in the Electric Potential

    Homework Statement A proton is released from rest in a uniform electric field of magnitude 40000V/m di- rected along the positive x axis. The proton undergoes a displacement of 0.3 m in the di- rection of the electric field The mass of a proton is 1.672623×10−27 kg A.Find the...
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    Finding the initial and final charge of two spheres

    This is an online homework. It says I got A right but B is wrong. I will go back through and check my math. I just wanted to make sure the process was right.
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    Three Point Charges in a Row, Find Magnitude 1.5cm left of middle charge

    So now E1=8.76*10^7 E2=1.8*10^8 E3=9.66*10^6 so, Enet=E1-E2+E3 Did I get the signs right?
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    Finding the initial and final charge of two spheres

    Homework Statement Two identical small metal spheres with q1 > 0 and |q1| > |q2| attract each other with a force of magnitude 70.2 mN, as shown. The spheres are then brought together until they are touching. At this point, the spheres are in electrical contact so that the charges...
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    Three Point Charges in a Row, Find Magnitude 1.5cm left of middle charge

    I am guessing the r should be different for each one... E1=k*q1/r^2 r=.044m -.015m=.029m E2=k*q2/r^2 r=.015m E3=k*q3/r^2 r=.046m +.015m=.061m
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    Three Point Charges in a Row, Find Magnitude 1.5cm left of middle charge

    Oh lol... Then I use E=F/q=kq/r^2 then do I calculate the E for each one? like so.. E1=k*q1/r^2 E2=k*q2/r^2 E3=k*q3/r^2 then what would r be?
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    Three Point Charges in a Row, Find Magnitude 1.5cm left of middle charge

    Homework Statement Consider three charges arranged as shown. + + - 1 2 3 What is the magnitude of the electric field strength at a point 1.5 cm to the left of the middle charge? The value of the Coulomb constant is 8.98755 × 10^9N  m2/C2. Answer in units of N/C q1=8.2 µC= 8.2*10^-6...
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    Point charges acting on a point

    So F(1 on 2)x=0 F(1 on 2) y=6.305*10^-4 but how do I apply this to F(q on 2) F(q on 2)x= F(q on 2) Cos 60 F(q on 2)y= F(q on 2) Sin 60 but F(q on 2)= k*Q*(2*10^-6)/(6.03)^2 and Q is unknown... also would 2F(q on 2)+F(1 on 2)=0
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    Point charges acting on a point

    So something like this? F (1 on 2)= k (4.4*10^-)(2*10^-6)/(11.12)^2 F(q on 2)= k*Q*(2*10^-6)/(6.03)^2
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    Point charges acting on a point

    Homework Statement Three point charges are located at the vertices of an equilateral triangle. The charge at the top vertex of the triangle is -4.4 µC. The two charges q at the bottom vertices of the triangle are equal. A fourth charge 2 µC is placed below the triangle on its symmetryaxis, and...
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    Finding the magnitude of the positive charge

    Two conducting spheres have identical radii. Initially they have charges of opposite sign and unequal magnitudes with the magnitude of the positive charge larger than the magnitude of the negative charge. They attract each other with a force of 0.231 N when separated by 0.5 m. The spheres are...
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