Recent content by fal01

Thanks! I was just missing the negative sign.

so what I started doing was right... (40000V/m)(.3m) =12000 V when I put in that answer it says I am wrong :(

Homework Statement A proton is released from rest in a uniform electric field of magnitude 40000V/m di- rected along the positive x axis. The proton undergoes a displacement of 0.3 m in the di- rection of the electric field The mass of a proton is 1.672623×10−27 kg A.Find the...

This is an online homework. It says I got A right but B is wrong. I will go back through and check my math. I just wanted to make sure the process was right.

Thanks so much! I got it! :)

So now E1=8.76*10^7 E2=1.8*10^8 E3=9.66*10^6 so, Enet=E1-E2+E3 Did I get the signs right?

Homework Statement Two identical small metal spheres with q1 > 0 and |q1| > |q2| attract each other with a force of magnitude 70.2 mN, as shown. The spheres are then brought together until they are touching. At this point, the spheres are in electrical contact so that the charges...

I am guessing the r should be different for each one... E1=k*q1/r^2 r=.044m -.015m=.029m E2=k*q2/r^2 r=.015m E3=k*q3/r^2 r=.046m +.015m=.061m

Oh lol... Then I use E=F/q=kq/r^2 then do I calculate the E for each one? like so.. E1=k*q1/r^2 E2=k*q2/r^2 E3=k*q3/r^2 then what would r be?

Homework Statement Consider three charges arranged as shown. + + - 1 2 3 What is the magnitude of the electric field strength at a point 1.5 cm to the left of the middle charge? The value of the Coulomb constant is 8.98755 × 10^9N
m2/C2. Answer in units of N/C q1=8.2 µC= 8.2*10^-6...

So F(1 on 2)x=0 F(1 on 2) y=6.305*10^-4 but how do I apply this to F(q on 2) F(q on 2)x= F(q on 2) Cos 60 F(q on 2)y= F(q on 2) Sin 60 but F(q on 2)= k*Q*(2*10^-6)/(6.03)^2 and Q is unknown... also would 2F(q on 2)+F(1 on 2)=0

So something like this? F (1 on 2)= k (4.4*10^-)(2*10^-6)/(11.12)^2 F(q on 2)= k*Q*(2*10^-6)/(6.03)^2

Homework Statement Three point charges are located at the vertices of an equilateral triangle. The charge at the top vertex of the triangle is -4.4 µC. The two charges q at the bottom vertices of the triangle are equal. A fourth charge 2 µC is placed below the triangle on its symmetryaxis, and...