Recent content by fattycakez

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    Orthogonal complement of the intersection of 2 planes

    Okay so how do you find the basis for W⊥ then?
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    Orthogonal complement of the intersection of 2 planes

    Okay sweet! So if (1,0,1) is the basis for W⊥, shouldn't there be one more basis vector since W⊥ is a plane and a plane is 2 dimensional?
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    Vector Reflection Across y=2x: Solving with Rotation and Change of Bases

    Man I'm slow, it makes an angle of 52.125! When I use that and the (5,1) in the rotation equations it looks like its reflecting in the wrong direction (4th quadrant rather then second quadrant) The new vector appears to be at a 90 degree angle with y=2x, do I need another rotation or...
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    Orthogonal complement of the intersection of 2 planes

    Homework Statement Let W be the intersection of the two planes: x-y+z=0 and x+y+z=0 Find a basis for and the dimension of the orthogonal complement, W⊥ Homework EquationsThe Attempt at a Solution The line x+z=0 intersects the plane, which is parameterized as t(1, 0, -1) Then W⊥ is the plane...
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    Vector Reflection Across y=2x: Solving with Rotation and Change of Bases

    Homework Statement Find the (exact) reflection of the vector v = (5, 1) across the line: y = 2x. Hint: A sketch of v and the line may suggest an approach. Homework Equations The Attempt at a Solution I found the matrix -3/5 6/5 4/5 2/5 which seems like it gives the reflection across y=2x...
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    Transition and coordinate matrices

    Homework Statement Consider the bases B = {b1,b2} and B' = {b'1,b'2} for R2, where b1=(1, -1), b2=(2,0), and b'1=(1,2), b'2=(1,-3) a. Find the transition matrix P from B to B' b. Compute the coordinate matrix [p]B, where p=(4,3); then use the transition matrix P to compute [p]B' Homework...
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    Standard matrix for reflection across the line y=-x

    Cool thanks, that makes sense! I learned everything I know about math from U of A, its not my fault :D
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    Standard matrix for reflection across the line y=-x

    It doesn't move then right? Its reflection is on its original location?
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    Standard matrix for reflection across the line y=-x

    It reflects onto the line but in the opposite quadrant?
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    Standard matrix for reflection across the line y=-x

    Thanks guys! How did you get that matrix? After fiddling with some numbers to try to get it to work I got T(-1, 1) = (-1, 1) which would be a point on the line y = -x so I guess all the points on the line wouldn't move obviously right?
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    Standard matrix for reflection across the line y=-x

    Homework Statement Let T : R2→R2, be the matrix operator for reflection across the line L : y = -x a. Find the standard matrix [T] by finding T(e1) and T(e2) b. Find a non-zero vector x such that T(x) = x c. Find a vector in the domain of T for which T(x,y) = (-3,5) Homework EquationsThe...
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    Find basis B given the transition matrix and B'

    Homework Statement The Matrix P = 1 0 3 1 1 0 0 3 1 is the transition matrix from what basis B to the basis B' = {(1,0,0),(1,1,0),(1,1,1) for R3? Homework Equations [v]B=P[v]B' The Attempt at a Solution I'm looking...
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    Points on lines with parametric equations (linear algebra)

    What would a general point on the parametric lines look like? The x, y, z components give in the problem? ( I haven't taken multi variable calc yet and this class assumes I will only use algebra to complete the homework)
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    Points on lines with parametric equations (linear algebra)

    Okay, will it have something to do with PQ ⋅ L1 = 0 and PQ ⋅L2 = 0? Or am I way off here?
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