Recent content by fishshoe

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    Jordan Basis for Differential Operator

    So do I need something like \begin{array}{ccc} 0 & 1 & 0 & \dots & 0 \\ 0 & 0 & 1 & \dots & 0 \\ \dots \\ 0 & 0 & 0 & \dots & 1 \\ 0 & 0 & 0 & \dots & 0 \end{array} as an n-vector Jordan basis for the polynomials of order up to n?
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    Jordan Basis for Differential Operator

    Homework Statement Let V = P_n(\textbf{F}) . Prove the differential operator D is nilpotent and find a Jordan basis. Homework Equations D(Ʃ a_k x^k ) = Ʃ k* a_k * x^{k-1} The Attempt at a Solution I already did the proof of D being nilpotent, which was easy. But we haven't covered...
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    Nilpotent operator or not given characteristic polynomial?

    Yeah - I hadn't thought about using that for a proof, but it would show that (-1)^{n}T^n = 0 \Rightarrow T^n = 0 so T is nilpotent. So what does this part (b) mean? T^n = 0 means T is nilpotent no matter if the field is complex or reals, right? Is it just a mean-hearted distraction...
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    Nilpotent operator or not given characteristic polynomial?

    Hey, I'm working on a proof for a research-related assignment. I posted it under homework, but it's a little abstract and I was hoping someone on this forum might have some advice: Homework Statement Suppose T:V \rightarrow V has characteristic polynomial p_{T}(t) = (-1)^{n}t^n. (a) Are...
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    Every nxn matrix can be written as a linear combination of matrices in GL(n,F)

    Okay, I figured it out. Nevermind (although once a post gets buried two screens back, it's not likely to be answered anyway, even if it has zero replies...).
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    The General Linear Group as a basis for all nxn matrices

    I'm trying to prove that every nxn matrix can be written as a linear combination of matrices in GL(n,F). I know all matrices in GL(n,F) are invertible and hence have linearly independent columns and rows. I was thinking perhaps there is something about the joint bases for the n-dimensional...
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    If a matrix commutes with all nxn matrices, then A must be scalar.

    So if I have A = diag(a_1,...,a_n), then A\vec{e_1} = a_1\vec{e_1} A\vec{e_2} = a_2\vec{e_2} ... A\vec{e_n} = a_n\vec{e_n} But a vector of all 1's should also be an eigenvector of A. A * (1,1,...,1)^T = (a_1, a_2, ..., a_n)^T And therefore this can only be an eigenvector if...
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    [Statistics] Conditional Probability questions?

    Also, the version of Bayes' Theorem you're using is more complex than you need to solve the first problem. The basic formula for conditional probability is P(B|A) = P(B \cap A)/P(A) So you know you're in A because that's given. So you want to know, what's the probability that you'll be in...
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    If a matrix commutes with all nxn matrices, then A must be scalar.

    So if A is a diagonal matrix in any bases β and γ, then [A]_β = diag(a_1,..., a_n) and [A]_γ = diag(b_1,..., b_n) And for the eigenvectors in any basis, [A]_βe_i = a_ie_i But I'm stuck there. How do I show that a_1 = a_2 = ... = a_n ?
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    [Statistics] Conditional Probability questions?

    When you say that P(AB) = P(A) * P(B), you're assuming that the two events are mutually exclusive. But since P(A|B) = 0.7, we know that's not true (otherwise P(A|B) = P(A)). What you want is the probability of A and B (i.e. their intersection).
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    If a matrix commutes with all nxn matrices, then A must be scalar.

    So since Av is in the same one-dimensional subspace as v, we know that Av is a scalar multiple of v, and so A is a scalar nxn matrix! But does this apply to any nxn matrix B? Or does it have something to do with the specific B that we defined, such that we have to generalize it further to prove...
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    If a matrix commutes with all nxn matrices, then A must be scalar.

    I'm trying to figure out what v, b2, b3,..., bn is a basis for. Is it for all nxn matrices? If Bv=v, then v is an eigenvector of B corresponding to eigenvalue λ=1, and B is the identity operator on the one-dimensional subspace spanned by v. I know that det(B-I) = 0, so maybe something...
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    [Statistics] Conditional Probability questions?

    It's not clear where your brackets end in Bayes's Theorem. Try this instead: P(B|A) = P(A|B) *(P(B))/(P(A))
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    If a matrix commutes with all nxn matrices, then A must be scalar.

    Homework Statement Prove: If a matrix A commutes with all matrices B \in M_{nxn}(F), then A must be scalar - i.e., A=diag.(λ,...,λ), for some λ \in F. Homework Equations If two nxn matrices A and B commute, then AB=BA. The Attempt at a Solution I understand that if A is scalar, it...
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    Every nxn matrix can be written as a linear combination of matrices in GL(n,F)

    Homework Statement Prove: Every nxn matrix can be written as a linear combination of matrices in GL(n,F). Homework Equations GL(n,F) = the set of all nxn invertible matrices over the field F together with the operation of matrix multiplication. The Attempt at a Solution I know all...
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