Recent content by Fjolvar

I'm having trouble figuring out how the term below boxed in red was eliminated on the left side of the equation as shown below. I reviewed properties of exponential functions, and still can't understand how this term was cancelled. 1. Homework Statement Homework Equations Exponential laws...

I'm not quite sure what you mean :/

I mean (-1/20 + 1/20) zeroes out V1 at node 2, since the dependent source is equal to 0.05V1

That's for the term in the first KCL equation. But V1 in the second equation equals zero which has me stuck. I can't set up my equations to find any of the unknowns.

My mistake. That should read (v1-8)/2. I'm still stuck on the second equation however since v1 equals zero. Am I missing something obvious here?

I tried solving this problem using KCL, but V1 keeps adding up to zero for my second set of equations. I'm not sure what I'm doing wrong. Any help is much appreciated. 1. Homework Statement I need to find the Thevenin equivalent circuit. I chose to find the Isc and the Voc by using KCL, since...

For some reason I'm having trouble determining what the voltage at terminal a would be. Since we only know the voltage drop across the 12 ohm resistor and not the voltage before, I'm not quite sure what other information we can use.

My mistake, I corrected the label of the node in the picture from 'a' to 'x'. I assumed there is only a voltage dissipation across the 12 ohm resistor, but no voltage before at node a, since there's only a current source. Wouldn't the voltage at x also be zero? Since there's no voltage at node...

So was the aha! moment supposed to be that i2 through the 10 ohm and 5 ohm resistor doesn't exist since the main current shorts back to the current source? Here is what I have for a final answer:

Thanks gneill. I've moved onto the second part now with only the current source in place, but I'm still having trouble seeing what to do next. I've spent some time trying different approaches such as KVL and KCL, but it's not quite working out. I was hoping a current divider would be possible...

Looks like I got ahead of myself. So the voltage at terminal a is 50 V making Vab (50-16.6) = 33.4V, correct?

I made another attempt, but wanted to make sure I'm on the right track before I go any further. Since there is no current flowing into the 12 ohm resistor branch, there is no voltage drop, right? Therefore I assumed Va = 0 and just calculated for the one loop containing the other two resistors...

So I made an attempt using Thevenin and Superposition, but I got stuck early into it. I'm not quite sure how to find the Thevenin voltage with the 50V source in place and the current source removed. I'm not sure how I would calculate the voltage drop over a and b terminals since there is no...

I've only taken a basic circuits course and that was years ago. Can anyone help me get this one started? 1. Homework Statement Homework Equations KCL The Attempt at a Solution [/B] I'm not sure if I should use KCL right away or use Thevenin. Since I need to find the current through the 2...

Thanks you Gneill, I see that now, however I'm still not sure how to approach this problem. I'm trying to solve for the current through all branches. Wouldn't the current I split into three branch currents R2+R5 & R3+R5 & R4?