Recent content by h1a8

nvm, i figured it out. I use "=SUMPRODUCT". In the place of "x" just put "ROW(1:1,000,000)" So for Sum([e^sin(atan(ln(3x^2+2x-3)))]^(1/3),x,1,1,000,000) just do: =SUMPRODUCT(POWER(EXP(SIN(ATAN(LN(3*POWER(ROW(1:1000000),2)+2*ROW(1:1000000)-3)))),1/3))

I totally forgot how to do this (it's been a long while). I'm thinking it was "=sumproduct" feature? Anyway I'm trying to find the sum of cuberoot(exp(sin(arctan(3x^2+2x-3))))) from x=1 to x=1,000,000 in excel. I believe you input ranges for the variable x. I'm not sure. I accidentally deleted...

How did you get the time 112 ms?

Yes I check all others (mathematica, maple, etc) The solution it gives is 1,395,279.57136 I looked at the guide. No dice. Keeps posting the actual code (probably wrong) I stead of the conversion.

Thanks That would make a lot of sense. Any idea how I would post the expression in Latex form for this forum? Edit: It still calculates the same speed while in airplane mode lol. I don't think it's the cloud.

Why is Desmos (graphing calculator app for Android, ios, windows, etc) far faster than everything else in calculating? I've done the same calculations in Mathematica, Maple, hp prime pro app on windows (ios and Android), various calculator apps on ios and Android, etc This is one of the things...

Wouldn't that be circular? Working backwards (assuming A's clock reads 12.5) to obtain results so that there is no contradiction. Is there a forward process (without graphs and assuming A's clock reads 12.5 at event 3) that tells us A's clock reads 8.5 in C's frame at event 2?

I don't see the logic of how C's line points to 8.5 on A's line at event 2.

How did you get that A's clock read 8.5 simultaneously to event 2 with reference to C?

Oh ok. I didn't quite understand you at first. So the first attempt is correct but not the 2nd attempt (for the 2nd question). So ignoring both event 1 and object B (making a more simpler scenario) and assuming that, according to frame C, it takes t = 5 to pass A after traveling v = 3/5c...

Simple problem? Wow I been at this for months. I feel slow lol. I have tried everything (looking at it in all frames, including A's). I don't like diagrams (I don't understand them that well). I rather use math equations. Using A's frame, I used Lorentz transform to derive that tA = 5/4tC (a...

Ok I understand that question 1 depends of which inertial frame (each frame gives a different answer). But I have no clue on how to answer question 2 when C passes A.

TWIN PARADOX Consider 3 objects, A, B, and C, in motion along the x direction. EVENT 1 B passes A while moving at a constant v = 3/5c relative to A. Both clocks set to t = 0. EVENT 2 C passes B when B’s clock reads t = 5 while C is moving at a constant v = 3/5c towards (and relative) to A...

Consider 3 objects, A, B, and C, in relative motion along the x direction. EVENT 1 B passes A while moving at a constant v = 3/5c relative to A. Both clocks set to t = 0. EVENT 2 C passes B when B’s clock reads t = 5 while C is moving at a constant v = 3/5c towards (and relative) to A. C’s...

Excellent Neil. But the g's in the final equation should be in the numerators (although it does not change the result).