Recent content by hddd123456789

Thank you, having looked a bit more, it looks like some type of game where you build atomic nuclei...fun!

Hello, I happened to randomly come upon a website showing some interesting images of the nucleus of different atoms in a layered format I've never seen before [external link redacted]. In fact, when I googled "nucleus layered view", a term found on the website, it only had similar image...

Yes this is generally what I'm talking about, though I didn't mean to imply any sort of restriction such as not considering values over the entire interval. It just so happens that I kept running into the fact that I know of no way of determining directly the indefinite integral without applying...

I hope I haven't missed anything, but the examples you gave all seem to deal with definite integrals, or if they obtain the indefinite integral, it is implied that derivation rules were applied in reverse (i.e. power rule, d/dx of ln(x)=1/x, etc.). As for the definite integral, if I recall...

Hello, I was just wondering, we have what could be called the indefinite derivative in the form of d/dx x^2=2x & evaluating at a particular x to get the definite derivative at that x. But with derivation, we can algebraically manipulate the limit definition of a derivative to actually evaluate...

Just watched Intersteller and my mind started running wild with all sort of fun thoughts. So I'm not sure how serious of a questions this is, but I got to thinking if it's possible to use gravity waves as a form of communication. And in turn, started wondering how said waves could be detected...

Yeah I see that now, thanks. integral of 1 x Yeah, it seems I was letting the geometric description over-rule the definitions. Can I still find it a bit weird that the geometric description holds for \int_b^1 1/x=ln(1)-ln(b) for b as close as you want to, but not equal to, zero lol, or am I...

Nvm then I don't get it lol, I still haven't gotten to improper integrals yet; so you're saying that \int 1/x=ln(x) is simply false over the interval [0,1]?

Got it, so is this one of those things that are just defined to be the way they are? I mean even though the definition I used was of an improper integral, just looking at the graph of 1/x really gives a counter-intuitive interpretation of what is going on: starting at 1, I'm seeing the area...

Hello, Just wondering about something, given that ln(1)=0, then the below should hold true? \int_0^1 1/x=0 But the entire graph from 0 to 1 of 1/x is positive, unbounded in fact to positive infinity. So is there an intuitive explanation for why the area under the graph of 1/x from 0 to 1...

Thanks for the reply! But actually it turned out to be some sort of programming glitch. My first huge mistake was to not add in data points for time periods that had no sales. I realized this and wrote the code to add in zeroes for these, but when I was still getting expected values that were...

Sorry, you mean understand the problem or the equation in your post? I know that S1 equals (1+a)^b as well as e. But I guess there isn't a similar closed form of S2. As for the problem, this is just some "fun" exploration of numbers I made up.

Hi, I've been working on trying to model sales for my work and I'm really just modeling it using exponential regression, so I get the linear regression of the logarithm of the data and obtain the desired formula. What I'm confused about is that if I integrate this to try to predict how many...

If you want some more food for thought, consider this: when you poke your finger across a 2D world, the 2D beings themselves won't see a circle since they will have 2D eyes and so will see in 1D :) Just as how we live in a 3D world with 3D eyes but see in 2D (although our brains make it look...

Thanks for the reply; would it help to set k=1 for both series, and deal with the first terms separately? And forgot to mention that S1=e.