Recent content by Hen Sharir

N is the normal force. (the force that Earth applies)

correct me if I'm wrong but I think the component of the applied force along the inclined surface should be ##Mgsinθ## as well (just to the opposite direction).

since the 2 masses are connected they should have the same acceleration

I spoke to my Chemistry teacher about it and she said that since NaOH is already VERY soluble in water the increase in temperature shouldn't have a noticeable effect on its equilibrium.

does it matter that solubility increases if in both cases all of the NaOH dissolves? edit: or well not ALL of it but in both cases, it reaches the equilibrium

ok so let me know if I understand right (from what I read in the link you shared). In exothermic reactions - as the initial temperature increases, dH/R becomes smaller hence dH being a smaller value? so if I apply this to the example I gave with NaOH - as I increase the initial temperature of...

Say I dissolve NaOH in water - a very exothermic reaction. Does it matter if I dissolve it in water that is at room temperature or at a different temperature? Will changing the initial temperature of the water affect the dH of the reaction (hence affect the change in temperature at the end of...