Recent content by IB

But how is 1g of anything = 6.022 X 10^23 amu Isn't 1 amu = 1/12 Carbon-12 so therefore 6.022 X 10^23 amu = 6.022 X 10^23 amu / 12 Carbon-12 ? I'm quite confused. Where did chemists get 1g of anything = 6.022 X 10^23 amu. :confused:

The textbook told me that there's a relationship between the amu and the gram, but I fail to see any. Could you please show me? Thank you.

What quantitative data can I gain from an experiment involving conductivity? And by the way, how do you know which one is polar covalent which one is non-polar covalent? How would you perform an experiment to test that? Thanks for your help, by the way! :)

So...how do you carry out an experiment to test if some unknowns are covalent (polar or non-polar) or ionic? Unknowns: C6H12O6 --NaCl --CH4N20 --C6H8O7 :confused:

Okay, for #3, there can be many cases (possibilities-which letters we choose, not their arrangements in the 4 letter word): (a) All four letters are different (MISP) 4*3*2*1=24 (b) If two letters repeat (2I, 2P or 2S) AND there is M There are 6 possibilities (M2IP/S; M2PI/S; M2SP/I)...

You got #1 right. It is indeed (11!)/(4!*4!*2!) = 34,650. -------------------------------------------------------- For #2: Step one: calculate all possible ways taking into account repetitions: 10!/(3!*3!*2!*2!) Step two: consider AAA as one letter and thus calculate in how many varinats they...

Tonight I've got so many hard problems... A 3.0 kg mass slides across a frictionless surface and collides against a spring bumper with a velocity of 3.0 m/s as shown in the diagram. Determine the maximum amount of the spring compresses if it spring constant is 335 N/m. For this one I don't...

F = M g sin (theta) ? I'm not sure what you mean. :confused:

A 2.0 kg mass slides down a frictionless inclined plane that makes an angle of 30 degrees with the horizontal. The sass starts from rest. What is its speed after it has slid a distance of 3.0 m along the incline? I got: F = (sin30)(9.8) F = 4.9 N W = Fd W = (4.9) (3) = 14.7 J W =...

Ahh, I see now. Thanks a lot, Doc Al. :)

Ohh, I forgot that. sqrt (7.84) = 2.8 --> Isn't that the minimum speed? if that's not the minimum speed, then...Hmm, how to find minimum speed..? Could the minimum speed of the pendulum be "0"? Or should we determine the minimum speed at exactly the highest point, when it gets its best...

A pendulum, with a 2.0 kg bob, is released from a height of 0.400 m and allowed to swing freely. Determine its minimum speed. I got: E_grav = E_kin --> mgh = 1/2 mv^2 --> v = sqrt (2gh) --> v = sqrt (2*9.8*.4) --> v = 7.84 m/s Is that right? It seems weird; so please tell me if I'm right...

Thanks so much, Diane_ :)

2(Tcos60)=150 Tcos60=75 T=150 Is that right? :) And for part b) I think 75.0 N is the most logical, yeah? It can't be less, cos otherwise it won't be able to hold 150.0 N. ---- First one: Force x distance: Forces going in one directon = 700x1 and 200 x 1.5 Forces going in other direction =...

Statics and Equilibrium Hi. I read and re-read these problems but I don't get them. Could you please show me how to do them? STATICS A 700.0N window washer is standing on a uniform scaffold supported by a vertical rope at each end. The scaffold weighs 200.0N and is 3.00m long. What is the force...