Recent content by Ishaan S

Conservation of momentum with the 2 objects applies since there is no net force in this system of 2 objects. Can you go from there?

Ok. Thank you very much. I get it now.

I forgot to mention, the problem in the attachment is number 5.

Homework Statement A uniform meter stick of mass M is pivoted on a hinge at one end and held horizontal by a spring with spring constant k attached at the other end. If the stick oscillates up and down slightly, what is its frequency? [Hint: Write a torque equation about the hinge.] The length...

OK. The mean distance is (1.521*108 km + 1.471*108 km)/2 = 1.496*108 km = 1.496*1011 m. Then the average velocity comes from the centripetal acceleration formula: Fa = FG = GM/(rave)2 = (vave)2 / rave Solve for vave vave = 30,000 m/s. So average KE = ,5mvave2 = 2.7*1033 J. Average...

Homework Statement The Earth's distance from the sun varies from 1.471 x 108 km to 1.521 x 108 km during the year. Determine the difference in (a) the potential energy, (b) the earth's kinetic energy, and (c) the total energy between these extreme points. Take the sun to be at rest. Homework...

Ok. So I set up an equation. Fnormal + mgcosθ = mv2/r where θ is the angle between the normal force and the gravitational force. I set Fnormal equal to zero because when the object leaves the track, the normal force would be 0. mgcosθ = mv2/r I solved for v2. v2 = rgcosθ I then set up...

1. Homework Statement A small mass m slides without friction along the looped apparatus shown in the attached file. (a) If the object is to remain on the track, even at the top of the circle(whose radius is r), from what minimum height hm must it be released(from rest)? (b) If it is released at...

Yes, this is correct. With parabolas, the acceleration would be constant; however, how would one possibly be able to know that this curve has a uniform acceleration without the use of calculus to prove it? Someone would have probably already told you that the curve had a constant acceleration...

Never mind, I just figured it out.

Wait, but don't we want the acceleration to be zero?

Ok, thanks. I appreciate your help very much. I'll see if I can go on from there.

Sorry, but I'm not understanding why one should add the centripetal and gravitational forces perpendicular to the surface rather than subtracting them to get the normal force. Aren't they in the opposite directions?

Was it the normal force? Should I make it FG(perpendicular) - FC(perpendicular)?

Could you please tell me if anything is wrong with the diagram I had attached a few minutes ago?