Recent content by jaxta

I looked over it again and that didn't really work out. So angle ADC is 180 minus 120°31'21" . This equals 59°28'39" you said this would equal the bearing DC, however the bearing DC is already given in the question which is 87°29'. I don't know what i did wrong.

Thanks for your help, but I'm still wondering how to find the bearing AD which is (208°00'20"). I found the angle for BDA (120°31'21") do i need to do something with that to find bearing AD, I am still confused.

Hey, I am studying for a test and i am having trouble with this problem. I have attached a photo of the worked solution. For the first part of the triangle (ABD) I understand everything except how they got the bearing AD. How do you find this bearing from the angle BAD.

it turns out there had to be another line of discontinuity (blue line) at 12 metres which seems rather pointless

thanks, that is what i thought. It must be the way i have entered it in or something, i am going to try it again

I have drawn the following shear force diagram however it says it is wrong. Could somebody please explain to me what is wrong with it. The points in the diagram are 0 then -4 then 1.25 then 1.25, then back to 0.

Thank you, I have figured it all out. However i am having trouble with the next part of the question which says to check EK, KL and KF using method of sections. When doing this do i only use the external forces?

oopps sorry for the double posts, how do i delete them

ok if F_hj does equal to zero, i think i have figured out how to continue, could someone please analyse joint c. would the sum of the forces in the x direction be F_cd + F_cj cos45 and the sum in the y direction be F_ch -F_cj sin45 - 65N ?

thanks for your quick response. so F_ch must equal zero as well. i redid my calculations for the reaction forces and i got Ay=65N and By=55N. Also could somebody give me an example on how to analyse one of the joints because i don't really know how to go about it.

ok if F_hj does equal to zero, i think i have figured out how to continue, could someone please analyse joint c. would the sum of the forces in the x direction be F_cd + F_cj cos45 and the sum in the y direction be F_ch -F_cj sin45 - 65N ?

thanks for your quick response. so F_ch must equal zero as well. i redid my calculations for the reaction forces and i got Ay=65N and By=55N. Also could somebody give me an example on how to analyse one of the joints because i don't really know how to go about it.

The question is to calculate the forces ina ll members of the trussnby method of joints. First i have calculated the reaction forces for A and B by taking the moment from both these points. These came too: Ay=25N and By=25N I do not know where to go from here, what point should i analyse...