I seem to have figured this out for myself.
The Ma on the left side of my equation needed to be only the mass of the block in question. It seems that for systems of two blocks where one block is on a horizontal plane the M in Ma is only the block that is hanging freely and has accel due to...
I need some clarification here...
Homework Statement
There are two masses and a pulley.
The pulley has R = .12m and I = .09 kgm^2
Mass 1 in hangs freely in the air and is 4kg
mass 2 is on a table(no friction) and is 6kg
I am finding the magnitude of the accel of mass 1...
Thank you SammyS for your reply your hint lead me to the proper proof. I was having a hard time figuring out why it would be (3(2m)+1) and (3(2m+1)+1) instead of just (3(m+1)+1) ect... But i think i get it now.
Thanks very much
Homework Statement
2n-1
Sigma (3i+1) = n(6n-1)
i=0
prove for all positive n
Homework Equations
The Attempt at a Solution
It holds true for n=1
5=5
then P: m+1
2m+1
Sigma(3i+1) = (m+1)(6(m+1)-1) or 6m^2 + 11m + 5
i=0
then 2m+1
Sigma(3i+1) = m(6m-1) +...