Colebrook yields 0.0234 sorry I added an extra zero, typo.
Colebrook yields 0.04142 with the original flow rate. I assure you all the calculations are correct. Thank-you. Again colebrook wouldn't be the value I would assign the highest amount of accuracy for transition flows, and therefore...
colebrook yields 0.00234, however it is only valid at Turbulent Flows. I realize the confusion, earlier i wrote colebrook yields 0.99, that is incorrect. f = 0.99 is an equation that was developed to represent transition flows. However in this case a friction factor of 0.99 probably wouldn't...
Yes Indeed Darcy-Weisbach is indeed the equation to use!
The value of e for copper piping was 0.000005 ft/ft
straight from the moody diagram: f around 0.04
The issue comes from the range of uncertainty that exists when fluids are flowing in the transition / critical region. As you...
haha, unfortunately I don't have that kind of time either! but I agree it would be interesting to see the results to help better predict losses in piping systems.
Without a doubt its better to be safe if your not confident with the accuracy of the analysis. If 1/2" pipe could be used it...
Thanks for the reply!
That site was pretty useful in explaining a few things. How can I have a better understanding of what the real head loss would be? I tried using a few of those equations from that site which were appropriate for my Re:
Using Serghides Equation: f = 0.04
Using...
Hey everyone! I'm trying to determine the losses through a pipe network that consists of 254.5 feet of 0.75 inch diameter copper pipe.
The flow rate is 0.37125 gpm, with a corresponding velocity of 0.26962 fps. The fluid is water at 150 degrees F.
Based off that information, I have a...
alright thank's borek, I thought I would be able to just write it off but that's the farthest off we've ever been, so I figured I'd ask for a second opinion.
Calculating alkalinity and expressing it in "as CaCO3"
Homework Statement
Convert the following from milligrams per liter as the ion to milligrams per liter as CaCO3.
A) 83.00 mg/L Ca2+
B) 27.00 mg/L Mg2+
C) 48.00 mg/L CO2
D) 220.00 mg/L HCO3-
E) 15.00 mg/L CO32-
Homework...
Homework Statement
A metal rod having a diameter of 10 mm is subjected to a repeated tensile load. The material of the rod has a tensile strength of 290 MPa. How many load repetitions can be applied to this rod before it fails if the magnitude of the load is (a) 5 kN, and (b) 11 kN...
Homework Statement
Ethylene diamine tetra-acetic acid (EDTA) is a water-soluble compound that readily combines with metals, such as calcium, magnesium, and iron. The molecular formula for EDTA is C10N2O8H16. Assume one EDTA molecule complexes (associates with) one metal atom.
A factory...
I thought you would have to use that 43% in there somewhere, but I'm not sure how to use it. It would be nice if I still owned my chem book.
UPDATE:
Ok I tried re-working the problem again, here's what I came up with:
0.79 kg/L * 0.43 L / 1 L * 1000 g / 1 kg * 1 mol / 46.07 g = 7.37 M...
Homework Statement
Elemental (metallic) aluminum (Al) is reacted with HCl to yield aluminum chloride (AlCl3) and hydrogen gas (H2). How many grams of metallic aluminum would be required to produce 1 gram of pure hydrogen gas?
Homework Equations
Al + HCl --> AlCl3 + H2
Balance...
Homework Statement
Eighty-six proof whiskey is 43 percent ethyl alcohol, CH3CH2OH, by volume. If the density of ethyl alcohol is 0.79 kg/L, what is the molarity in whiskey.
Homework Equations
Molar Mass of CH3CH2OH = 46.07 g
The Attempt at a Solution
0.79 kg/L * 1000 g/kg * 1...
nvn: thanks for responding, I do use the full value during intermediate calculations but just for the purpose of posting here i shortened it some to save time.
After reading your response I went back and thought about it some more, here's my new attempt at a solution:
σx = P/A = 2000 psi...