Recent content by JonNash

Got it. I got the range formula wrong. the answer is c)

Homework Statement A stone is thrown with an initial velocity 5m/s such that it covers maximum possible horizontal distance RE on the surface of the Earth. The same stone is thrown with same initial velocity by a person standing on the moon, making an angle of 150 with the surface. given that...

Homework Statement A uniform magnetic field B is perpendicular to the plane of a circular wire loop of radius R. The magnitude of the field varies with time according to B=B0exp(-t/τ) where B0 and τ are constants. The time dependence of the induced emf in the loop is a) exp(-t2/τ2) b)...

Ohkay. Mass = m0c2 = 0.5MeV. Armed with this when I solved I got √8x1010cm/s as the velocity which translates to 2.828x1010cm/s which closely matches option b). Thanks hilbert2.

I solved it with the formula you gave and I got a complex number v=√-81x1052 I solved it with kinetic energy too and I got v=0. Ugghh...

To double the size of the system we would need to provide double the internal energy so U becomes 2U, then the volume would also double and since the volume increases the density decreases by 2 and so does the pressure, that means the entropy would also decrease by 2 so I have the equation...

Thanks for explaining that hilbert2. I calculated it and got the answer 3C/a^3. I know it was a noob question but I'm a bit new to this.

Homework Statement For an electron having energy 1.5MeV/c (mass of an electron is 0.5MeV), the velocity is given by? a) 2.92x1010 cm/sec b) 2.81x1010 cm/sec c) 2.75x1010 cm/sec d) 2.50x1010 cm/sec Homework Equations Kinetic Energy = 0.5mv2 The Attempt at a Solution I first...

In the absence of any source of charge/current the Gauss' law states that the divergence of an electric field is zero. In this case although we are given a field it is given in the absence of any source, wouldn't that mean that density/permittivity then would also equate zero, finally giving the...

All of them are extensive. Still don't get how to work the problem out. Did you get the answer? The options are a) 1 b) 1/3 c) -1/3 d) 3/4

Given that internal energy is measured in Joules, LHS becomes J and RHS is (J/k)*m3 So to equate in terms of thermodynamic quantities we could multiply with T=1k and P=1N/m2 and divide it by enthalpy (H)=1J, but there is no relation such as this, is there?

Yes, that's the equation, new here, having trouble with writing complex equations. I didn't get that. No problem at origin means its undefined there or well-defined even at the origin? If yes, how does Gauss' law remain intact? That's the whole problem, no boundaries for the surface...

Homework Statement The internal energy of a system is expressed by function U(S.V)=S4/3Vα, where α is a constant. The value of α is? The Attempt at a Solution Here internal energy is expressed in terms of volume and entropy but all the relations (as far as I know) are in terms of...

Homework Statement Let the electric field in a certain region of space be given by E(\vec{}r)=C\vec{}r/ε0a3, where a has dimension length and C is a constant. The charge density is given by? Homework Equations ∇.E=ρ/ε The Attempt at a Solution I've been searching this on the net...

Alright then it is resolved, d) is the right choice. Thanks Chet and Aleph.