Recent content by JoshP-hillips

Thanks for the tip, and moving the thread. Here's what I've done; NEW standard form (from old one) dy/dx + (1/x)y = sinx Integrating factor now becomes I(x) = e|(1/x)dx = elnx = x Multiplying both sides of the d.e. by I(x) gives; x dy/dx + x(1/x)y = x sinx x dy/dx + y = x sinx Rewriting...

Q1. x2dy/dx + xy = x2sinx I believe it is a separable equation (first order linear) First step is to rewrite into standard form; dy/dx + (xy)/x2 = (x2sin(x))/x2 Then to calculate the integrating factor I(x); I(x) = e|(xy)/x2dx = eylnx = elnxy = xy Then i need to multiply both sides of...

Well initially I thought the probability would be (1/6)*5 + (4/6) => 9/6 The 1/6 being the chance of rolling a 1-5 The 4/6 being the chance of rolling a 6 (It being 4 times more likely) But then I came up with a more logical answer; Probability of rolling a 1-5 x = P(D1-5) Probability of...

G'day, I've recently been given a probability question to solve and I'm not 100% on my approach towards it. It goes as follows; A dice is found to be weighted so that the chance of throwing a 6 is four times the chance of throwing a 1. Chances of throwing numbers other than 6 are equally...

Homework Statement The charge Q of the semiconductor diod has been shown through experiment to vary with the applied voltage V. This relationship can be expressed as: Q(V) = Q0 ln(1 + V/V0) Where Q0 and V0 are some constant reference values measured in Coulombs and Volts correspondingly...