Thanks for the tip, and moving the thread.
Here's what I've done;
NEW standard form (from old one)
dy/dx + (1/x)y = sinx
Integrating factor now becomes
I(x) = e|(1/x)dx = elnx = x
Multiplying both sides of the d.e. by I(x) gives;
x dy/dx + x(1/x)y = x sinx
x dy/dx + y = x sinx
Rewriting...
Q1.
x2dy/dx + xy = x2sinx
I believe it is a separable equation (first order linear)
First step is to rewrite into standard form;
dy/dx + (xy)/x2 = (x2sin(x))/x2
Then to calculate the integrating factor I(x);
I(x) = e|(xy)/x2dx = eylnx = elnxy = xy
Then i need to multiply both sides of...
Well initially I thought the probability would be (1/6)*5 + (4/6) => 9/6
The 1/6 being the chance of rolling a 1-5
The 4/6 being the chance of rolling a 6 (It being 4 times more likely)
But then I came up with a more logical answer;
Probability of rolling a 1-5
x = P(D1-5)
Probability of...
G'day,
I've recently been given a probability question to solve and I'm not 100% on my approach towards it.
It goes as follows;
A dice is found to be weighted so that the chance of throwing a 6 is four times the chance of throwing a 1. Chances of throwing numbers other than 6 are equally...
Homework Statement
The charge Q of the semiconductor diod has been shown through experiment to vary with the applied voltage V. This relationship can be expressed as:
Q(V) = Q0 ln(1 + V/V0)
Where Q0 and V0 are some constant reference values measured in Coulombs and Volts correspondingly...