Recent content by jspek9

Hello everyone, I started back to school a couple of years ago pursuing a BS in mechanical engineering. I'm moving at a snails pace just able to take a night class or two a semester getting my math, science, and physics out of the way at a local Jr collage. But I haven't got to any actual...

u=lnx dv= dx du= 1/x dx v=x =xlnx-integral(1)dx = xlnx-x+c lnx using IBP:)

oooooooohhhhh it doesn't fit the form the way i was trying to use it. i probably should have looked up the form before i got so frustrated. oh well ill know next time thanks for the help:)

I'm using u= asinθ so sinθ= x/3 & dx = 3cosθ dθ & 3cosθ = 9-x2 so subing in I get the integral 3cosθ/3cosθ dθ which reduces to one and equates to x after integration. The thing is this is really an improper integral problem Integral from 0 to 3 of 1/(9-x2) so if I get x...

the problem is integrate 1/(9-x^2)dx. For some reason I'm just drawing a blank. I've tried to fit arccot, ln, and trig sub and get nowhere. Is it part frac decomp? I don't know i think I'm just making it harder than it is. any insight is appreciated.

OK I've been looking at my potential energy formulas and I don't see the connection. I can't figure out what in the world I'm missing. On a side note just curious but is Spoon for Spoon Sports?:smile:

Homework Statement A relaxed spring with spring constant k = 70 N/m is stretched a distance di = 63 cm and held there. A block of mass M = 7 kg is attached to the spring. The spring is then released from rest and contracts, dragging the block across a rough horizontal floor until it stops...

A 800 gm block slides down an inclined plane that makes an angle of 30° with the horizontal. It accelerates at 1.5 m/s2. uk=.4 Find the magnitude and direction of the total force exerted on the block by the plane. For the direction, give the angle as measured counterclockwise from the vertical...

anyone?

The only way I now how to solve force of a spring is using Hookes Law, and I can't seem to make that work either. Is there any other advice you can give me? Could it have something to do with my original displacement is in m and the second part is in cm?

Can someone please check my equations to see if I am going about this the right way. A 0.4 kg tennis ball is dropped from rest at a height of 3.9 m onto a hard floor. a) What is the speed of the ball at the instant of contact with the floor? I solved to be 8.743 A flash photograph shows...

am I wrong assuming the final velociy of car B is 6 m/s at T=5?

can you be a little more specific? I can't seem to find anything in the text about how to go about seting these up.

one more quick question though the next question is asking what is the speed and magnitude of acceleration of car B relative to A What exactly do they mean by relative?

I see what your saying. The initial velocity isn't 1.2 its 0. That makes sense and gives a correct answer. thanks for the help. This is the first time I have used this site and you guys where great.:!) Thanks again.