ekinnike
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i can't find it anywhere. please help. i need to kno the inegration of lnx to find an area. please help thx
lol i didnt learn those yet. BUt I am glad it more complicated than it look. NO i can't do it. BUt i really appriciated the help. Instead i will try use simpsons rule. the question is area under the curve. 2day is monday-im at school school today so i quickly ask one of the mathematics teacher. =) i think he also hesitated say u can solve them by harder way but instead he told me simpson ruleVietDao29 said:Integration is a Calculus topic, and therefore, should not be posted in the Precalculus section.
Anyway, to integrate ln(x), we use Integration by Parts (have you covered Integration by Parts yet?), i.e:
\int u dv = uv - \int v du
We often use Integration by Parts, when no other methods can solve the integral.
So, we want to integrate this:
\int \ln (x) dx
We then let u = ln(x), and dv = dx
So that implies du = dx / x, and v = x.
Substitute all those into the formula, we have:
\int \ln (x) dx = x \ln (x) - \int x \times \frac{dx}{x} = ...
Can you go from here? :)