I thought the pressure would not have the ##\theta## component because of the symmetry and so there will be no ##\theta## component of the force as well. If ##\theta## is included I am stooped of what to do. I would assume in that case the flow velocity would have the tangential component, and...
Ahh, I see. I get that:
$$v_r = \frac{r\frac{dh}{dt}}{2(\frac{r^2}{2}(\frac{1}{b}-\frac{1}{a} - h)}$$
Should I now use this in the Navier Stokes equation (without inertial terms) to find pressure?
Thanks for the corrections. I misunderstood what z_a is at first. I have calculated the volume again:
$$ V = \pi r^2 (h+\frac{r^2}{4}(\frac{1}{a}-\frac{1}{b}))$$
Then, the rate of change of volume becomes:
$$ \frac{dV}{dt} = \pi r^2 \frac{dh}{dt}$$
Could you please advise why we need it?
I am a bit confused as to why there is a minus sign in H(r) (the answer for the force has a plus).
What I did is the following: if we position the spheres vertically, I thought of looking at the gap between the two spheres in a way that we move the bigger sphere upwards and the smaller one...
Thanks for your reply. Could you please hint me on how the first approximation for H can be achieved. I suppose since you mentioned for r small compared to the radii of the spheres, Taylor expansion should be used somewhere?
I solved a similar problem with a rigid plane and a circular disk of radius a. I followed the same procedure but for the limits of the integral it was easier to find them and they were just from 0 to a. However, here I am struggling to find the limits.
Homework Statement
Show that the force resisting change of the minimum distance h between the surfaces of two rigid spheres of radii a and b which are nearly touching is:
$$6\pi\frac{\mu}{h({a^{-1} + b^{-1}})^2}\frac{dh}{dt}$$
provided
$$\frac{\rho h}{\mu}\frac{dh}{dt}$$
Homework Equations...
Yes, I did get an equation of a harmonic oscillator and, hence, found the frequency. However, my question is that is this sufficient for showing that ##\theta_0## is indeed stable equilibrium, i.e. that since we have equation of a harmonic oscillator, we conclude that it is stable equilibrium?
Thank you for your reply! Yes, you are correct there is a missing R in the denominator for w_0 and yes, I should not have treated θ_0 as a small quantity - my mistake. This all makes sense now though!
The question also asks to show that θ_0 is a stable equilibrium, how can I can show this...
Homework Statement
A circular hoop of radius R rotates with angular frequency ω about a vertical axis coincident with its diameter. A bead of mass m slides frictionlessly under gravity on the hoop. Let θ be the bead’s angular position relative to the vertical (so that θ = 0 corresponds to the...
Homework Statement
Consider the curve C (image attached). C coincides with the real-z axis for $$|z| > a$$ and, in $$|z| < a$$ C coincides with the semi-circle $$|z| = a, =z > 0$$ In terms of simple singular flows, what is the image in C of a line source of strength 2πm lying at z = z_0, above...
Yes, I guess so since in what I have so far the units give something rather bizarre. When I was calculating v_0 I had: $$\vec{v_0} = r\dot{\theta}^2\mathbf{e}_\theta$$ in which I assumed $$\dot{r} = \dot{z} = 0$$
As for the angular momentum I don't quite see how factor m can appear in my...
Furthermore: an equation like $$
\dot{r} = \dot{r}\mathbf{e}_r + r\dot{\theta}\mathbf{e}_{\theta} + \dot{z}\mathbf{k}$$ is very confusing. How about$$
\dot{\vec r} = \dot{\rho}\mathbf{e}_\rho + \rho\dot{\theta}\mathbf{e}_{\theta} + \dot{z}\mathbf{k}\ \ ?$$
Yes I agree, it should be a vector -...