Recent content by kabailey

anybody?

In a mathematical model, a gas is under a pressure of the form P=e-v2 (v is volume). Find the work (in Joules) done on the gas as its volume decreases from infinity to zero. dW = PdV Solution Attempt: W=∫0∞e-v2dV http://en.wikipedia.org/wiki/Gaussian_integral Gaussian...

thank you for your help. my final answer is W=(√∏)/2

I was not familiar with the Gaussian intergral. Well since it's only half the distance I would divide by 2 ∴ W=∫0∞e-v2dV =(√∏)/2|∞0 so does that mean that the interval of ∞ to 0 is negligible?

W=∫0∞PdV P=e-v2 Do I simply substitue P in the original equation, differentiate, then integrate? W=∫0∞e-v2dV W=∫0∞(e-v2)/2v So far is this correct?

W=∫v1v2PdV ∴W=∫0∞PdV Would he just simply substitute his P in this formula?

I did not use the m(v^2/r)=kx. I was curious as to why one could not use this relationship. m(v^2/r) is to be used in an uniform circle and this system would not produce an uniform circle, thus one would yield an incorrect result. Thank you for all of your help sweet springs.

thank you!

understood, but does m(v^2/r) only apply to a circle?

Relaxed spring is sitting on a horizontal surface. A block is attached at one of its ends is kicked with a horizontal velocity, v1, given to it. The block will move and stretch. Find the distance, x, the spring will stretch. X is in meters. Energy 1/2 mv1^2 = 1/2 mv2^2 + 1/2 k x^2...

Question regarding this problem, how come I cannot use ma=m(v^2/r)=kx to solve this equation?

Sweet Springs thank you for your help! The final equation I get is x^3+2(x^2)-2=0, which gives me 0.839m as the final answer

Sorry I did not notice your post. The extension is at 90 degrees.

Solving for x in the energy equation, I get x=1/v2 Substituting 1/v2 in the angular momentum equation, I get v2=0. When I go back to solve for x, I get x=0. Is this correct?

yes it makes sense. similar to the idea of conservation of momentum, P=m*v.I also understand kinetic energy initial will equal kinetic energy final.